6a. 1 - 2sin(x)² - 2cos(x)² = 1 - 2(sin(x)² +cos(x)²) = 1 - 2·1 = -1
6c. tan(x) + sin(x)/cos(x) = tan(x) + tan(x) = 2tan(x)
6e. 3sin(x) + tan(x)cos(x) = 3sin(x) + (sin(x)/cos(x))cos(x) = 3sin(x) +sin(x) = 4sin(x)
6g. 1 - cos(x)²tan(x)² = 1 - cos(x)²·(sin(x)²)/cos(x)²) = 1 -sin(x)² = cos(x)²
Answer/Step-by-step explanation:
1. 7x + 2 = 5x + 22 (alternate interior angles are congruent)
Collect like terms
7x - 5x = -2 + 22
2x = 20
2x/2 = 20/2
x = 10
2. 13x - 6 = 10x + 24 (alternate interior angles are congruent)
Collect like terms
13x - 10x = 6 + 24
3x = 30
3x/3 = 30/3
x = 10
3. (12x + 26)° + 46° = 180° (same side interior angles are supplementary)
12x + 26 + 46 = 180
12x + 72 = 180
12x + 72 - 72 = 180 - 72
12x = 108
12x/12 = 108/12
x = 9
4. (5x + 5)° + 135° = 180° (same side interior angles are supplementary)
5x + 5 + 135 = 180
5x + 140 = 180
5x + 140 - 140 = 180 - 140
5x = 40
5x/5 = 40/5
x = 8
Answer:
The probability is either 2 but mostly 3 boys.
Step-by-step explanation:
Answer:
because they have little anty bodies.
Step-by-step explanation:
i don't know
- <u>A </u><u>triangle </u><u>with </u><u>sides </u><u>11m</u><u>, </u><u> </u><u>13m </u><u>and </u><u>18m</u>
- <u>We</u><u> </u><u>have </u><u>to </u><u>check </u><u>it </u><u>whether </u><u>it </u><u>is </u><u>right </u><u>angled </u><u>triangle </u><u>or </u><u>not</u><u>? </u>
According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.
<u>We </u><u>imply</u><u> </u><u>it </u><u>in </u><u>the </u><u>given </u><u>triangle </u><u>,</u>
<u>From </u><u>Above </u><u>we </u><u>can </u><u>conclude </u><u>that</u><u>, </u>
The sum of the squares of two small sides that is perpendicular height and base is not equal to the square of longest side that is Hypotenuse
