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Lady bird [3.3K]
4 years ago
6

During a 360 minute school day the students are allowed 5 minutes for passing period to

Mathematics
1 answer:
LUCKY_DIMON [66]4 years ago
5 0

Answer: 41 minutes

Step-by-step explanation: 360 - 43 = 317

6 x 5 = 30

317 -  30 = 287

287 divided by 7 = 41 minutes

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Which function has the range
s344n2d4d5 [400]

Answer: C; y=csc(x)+1

Step-by-step explanation: just graphed them on desmos until i got the right one :)

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4 years ago
Examination of a large sample of people revealed a relationship between calcium intake and blood pressure. The relationship was
Vika [28.1K]

Answer:

a) The 95% confidence interval for the mean is (-1.171, 11.717).

b) No, there is not enough evidence to support the claim that increasing the amount of calcium in our diet reduce blood pressure (at a 5% significance level).

Step-by-step explanation:

The data for both groups are:

Group 1 (calcium): 7 -4 18 17 -3 -5 1 10 11 -2

Group 2 (placebo): -1 12 -1 -3 3 -5 5 2 -11 -1 -3

The mean and standard deviation for Group 1 is:

M_1=\dfrac{1}{10}\sum_{i=1}^{10}(7+(-4)+18+17+(-3)+(-5)+1+10+11+(-2))\\\\\\ M_1=\dfrac{50}{10}=5

s_1=\sqrt{\dfrac{1}{(n-1)}\sum_{i=1}^{10}(x_i-M)^2}\\\\\\

s_1=\sqrt{\dfrac{1}{9}\cdot [(7-(5))^2+(-4-(5))^2+...+(-2-(5))^2]}\\\\\\

s_1=\sqrt{\dfrac{1}{9}\cdot [(4)+(81)+(169)+(144)+(64)+(100)+(16)+(25)+(36)+(49)]}\\\\\\s_1=\sqrt{\dfrac{688}{9}}=\sqrt{76.44}\\\\\\s_1=8.743

The mean and standard deviation for Group 2 is:

M_2=\dfrac{1}{11}\sum_{i=1}^{11}((-1)+12+(-1)+(-3)+3+(-5)+5+2+(-11)+(-1)+(-3))\\\\\\ M_2=\dfrac{-3}{11}=-0.273

s_2=\sqrt{\dfrac{1}{(n-1)}\sum_{i=1}^{11}(x_i-M)^2}\\\\\\

s_2=\sqrt{\dfrac{1}{10}\cdot [(-1-(-0.273))^2+(12-(-0.273))^2+...+(-3-(-0.273))^2]}\\\\\\

s_2=\sqrt{\dfrac{1}{10}\cdot [(0.53)+(150.62)+...+(115.07)+(0.53)+(7.44)]}\\\\\\s_2=\sqrt{\dfrac{348.182}{10}}=\sqrt{34.82}\\\\\\s_2=5.901

a) We have to calculate a 95% confidence interval for the difference between means, with a T-model.

The Group 1, of size n1=10 has a mean of 5 and a standard deviation of 8.743.

The Group 2, of size n2=11 has a mean of -0.273 and a standard deviation of 5.901.

The difference between sample means is Md=5.273.

M_d=M_1-M_2=5-(-0.273)=5.273

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{8.743^2}{10}+\dfrac{5.901^2}{11}}\\\\\\s_{M_d}=\sqrt{7.644+3.166}=\sqrt{10.81}=3.288

The degrees of freedom for this test are:

df=n_1+n_2-1=10+11-2=19

The critical t-value for a 95% confidence interval and 19 degrees of freedom is t=1.96.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_{M_d}=1.96 \cdot 3.288=6.444

Then, the lower and upper bounds of the confidence interval are:

LL=M_d-t \cdot s_{M_d} = 5.273-6.444=-1.171\\\\UL=M_d+t \cdot s_{M_d} = 5.273+6.444=11.717

The 95% confidence interval for the mean is (-1.171, 11.717).

b) This is a hypothesis test for the difference between populations means.

The claim is that increasing the amount of calcium in our diet reduce blood pressure.

Then, the null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2> 0

The significance level is 0.05.

The sample 1, of size n1=10 has a mean of 5 and a standard deviation of 8.743.

The sample 1, of size n1=11 has a mean of -0.273 and a standard deviation of 5.901.

The difference between sample means is Md=5.273.

M_d=M_1-M_2=5-(-0.273)=5.273

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{8.743^2}{10}+\dfrac{5.901^2}{11}}\\\\\\s_{M_d}=\sqrt{7.644+3.166}=\sqrt{10.81}=3.288

Then, we can calculate the t-statistic as:

t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{5.273-0}{3.288}=\dfrac{5.273}{3.288}=1.604

The degrees of freedom for this test are:

df=n_1+n_2-1=10+11-2=19

This test is a right-tailed test, with 19 degrees of freedom and t=1.604, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>1.604)=0.063

As the P-value (0.063) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that increasing the amount of calcium in our diet reduce blood pressure.

4 0
3 years ago
What is the value of 3 x squared plus space 4 y squared if x = 2, y = 1, and z = –3?
RUDIKE [14]
The answer to the question is equal to 16
7 0
3 years ago
How do I find the area of a parallelogram?
aliya0001 [1]

Answer:

Area= base×height

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A door to a playhouse is 50 inches tall. Which of the following is another measure equal to the height?
-Dominant- [34]
The complete question in the attached figure

we have that
<span>A door to a playhouse is 50 inches tall

we know that
1 in---------------> is 0.0833333 ft
so
50 in-------------> 50*0.0833333---------> 4.167 ft
</span>4.167 ft----------> [4 ft+0.167 ft]
<span>remember that
</span>1 in---------------> is 0.0833333 ft
<span>X in----------------> 0.167 ft
X=0.167/0.0833333----------> X=2 in

therefore

</span>4.167 ft----------> [4 ft+0.167 ft]--------> [4 ft+2 in]<span>


the answer is
the option b) 4 ft 2 in


</span>

8 0
3 years ago
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