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3 years ago

Which orbital that would never exist in the quantum description of an atom is _____.

Chemistry

1 answer:

Anton [14]3 years ago

5 0

Answer:

C. 2s

Explanation:

the "s" orbital is only possible at an energy level of n = 1. 2s means the energy level is at n = 2 and that's not possible for the "s" sublevel.

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¿cual es la valencia mas probable para el sodio (Na)que se encuentra en el grupo 1 es?

igomit [66]

Answer:

Hey dude

Explanation:

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4 years ago

Which number represents a basic pH, 4 or 9

jekas [21]

I know 4 is acidic so it has to be 9

8 0

4 years ago

Read 2 more answers

A sample of nitrogen goes from 21L to 14L and it's pressure increases from 100kPa to 150kPa. The final temperature is 300K. What

Alik [6]

Answer:

The initial temperature is 300 K (The temperature doesn't change)

Explanation:

Step 1: Data given

Initial volume = 21L

Final volume = 14L

Initial pressure = 100 kPa = 0.986923 atm

Final pressure = 150 kPa = 1.48038 atm

The final temperature = 300K

Step 2: Calculate the initial temperature

Calculate the initial temperature

(P1*V1)/T1 = (P2*V2)/T2

⇒with P1 = the initial pressure = 0.986923 atm

⇒with V1 = the initial volume = 21 L

⇒ with T1 = the initial temperature = ?

⇒with P2 = the final pressure = 1.48038 atm

⇒with V2 = the final volume = 14 L

⇒with T2 = the final temperature = 300 K

(0.986923 * 21)/T1 = (1.48038*14)/300

T1 = 300 K

The initial temperature is 300 K (The temperature doesn't change)

8 0

4 years ago

#1. Which statement is a correct expression of the Law of Conservation of Mass? A. The total mass is unpredictable in a chemical

Cerrena [4.2K]

These are two questions and two answers.

Question 1: Law of Conservation of Mass

Answer: option B. The total mass remains the same during a chemical reaction.

Explanation:

The law of conservation of mass is a universal law. It states that mass is mass is neither created or destroyed, but is is conserved.

In chemical reactions, that means that, always, the total mass of the reactants equals the total mass of the products or, as the option B. states, during a chemical reaction the total mass remains the same.

Since, in chemical reactions, the atoms are not modified (the atoms just bond in different form or with different atoms), that implies that total number of each kind of atoms in the reactants equals the total number of the same kind of atoms in the products.

That is the basis for balancing the chemical equations and for the stoicheometric calculations.

Question 2 . Which element(s) are not balanced in this equation?

Answer: option A. Only the Fe is unbalanced.

Explanation:

1) Given equation: Fe₂O₃ + 3 CO → Fe + 3 CO₂

2) Count the number of atoms of each kind on each side of the equation

i) Fe

reactant side: 2

product side: 1

Therefore, Fe is not balanced

ii) O

reactant side: 3 + 3 = 6

Product side: 3 × 2 = 6

Therefore, it is balanced

iii) C

reactant side: 3

product side: 3

Therefore, C is balanced.

3) Conclusion: Only the Fe is unbalanced.

7 0

3 years ago

Read 2 more answers

A chemist wants to find Kc for the following reaction at 751 K: 2NH3(g) + 3 I2 (g) LaTeX: \Longleftrightarrow ⟺ 6HI(g) + N2(g) K

charle [14.2K]

Answer: The equilibrium constant for the total reaction is $4.09\times 10^{-6}$

Explanation:

We are given:

$K_{c_1}=0.282\\\\K_{c_2}=41$

We are given two intermediate equations:

Equation 1: $N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g);K_{c_1}=0.282$

The expression of $K_{c_1}$ for the above equation is:

$K_{c_1}=\frac{[NH_3]^2}{[N_2][H_2]^3}$

$0.282=\frac{[NH_3]^2}{[N_2][H_2]^3}$ .......(1)

Equation 2: $H_2(g)+I_2(g)\rightleftharpoons 2HI(g);K_{c_2}=41$

The expression of $K_{c_2}$ for the above equation is:

$K_{c_2}=\frac{[HI]^2}{[H_2][I_2]}$

$41=\frac{[HI]^2}{[H_2][I_2]}$ ......(2)

Cubing both the sides of equation 2, because we need 3 moles of HI in the main expression if equilibrium constant.

$(41)^3=\frac{[HI]^6}{[H_2]^3[I_2]^3}$

Now, dividing expression 1 by expression 2, we get:

$\frac{K_{c_1}}{K_{c_2}}=\left(\frac{\frac{[NH_3]^2}{[N_2][H_2]^3}}{\frac{[HI]^6}{[H_2]^3[l_2]^3}}\right)\\\\\\\frac{0.282}{68921}=\frac{[NH_3]^2[I_2]^3}{[N_2][HI]^6}$

$\frac{[NH_3]^2[I_2]^3}{[N_2][HI]^6}=4.09\times 10^{-6}$

The above expression is the expression for equilibrium constant of the total equation, which is:

$2NH_3(g)+3I_2(g)\rightleftharpoons 6HI(g)+N_2;K_c$

Hence, the equilibrium constant for the total reaction is $4.09\times 10^{-6}$

8 0

3 years ago