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larisa [96]
2 years ago
9

2.1d = 51.24 What is the answer?

Mathematics
1 answer:
erik [133]2 years ago
3 0
24.4 is the answer. c:
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The function h is a quadratic function whose graph is a translation 3 units left and 4 units up of the parent
jeka57 [31]

Answer:

D ( if you add +4 to the (x + 3)^2)

Step-by-step explanation:

Parent function is f(x) = x^2

A translation 3 units left gives y = )x + 3)^2

- and 4 up gives y = (x + 3)^2 + 4 - vertex form.

Standard form :

y = x^2 + 6x + 9 + 4

= x^2 + 6x + 13.

4 0
2 years ago
consider a wire 2 ft long cut into two pieces. one piece forms a circle with radius r and the other forms a square with side len
makkiz [27]

The formula for the radius r in terms of x . and for the maximum areas is x=2/\pi+4

Given that,

y forms a circle of radius r

y=2\pir

r=y/2\pi

(2-y)- forms Square Side x

(2-y) = 4x

x=(2-y)/4

Now Sum of Area's=Area of Square +Area of Circle

Sum = \pir² + x²

Substitute the r and x values in above equation,

A(y)= y²/4\pi+(y-2)²/ 16

To maximize Area A(y)

A'(y)= 0

2y/4\pi + 2(y-2)/16 =0

y/2\pi + (y-2)/8 =0

y = 2\pi/\pi+4

Y max will be max, x to be maximum.

for maximum sum of areas,

x=2/\pi+4

Hence,The formula for the radius r in terms of x . and for the maximum areas is x=2/\pi+4

Learn more about Area :

brainly.com/question/28642423

#SPJ4

4 0
1 year ago
Need help finding angles 1,2,3,4,5!!!!!
earnstyle [38]

Answer:

1. 18

2. 17

3. 26

4. 17

5. 18

4 0
2 years ago
If 2x/3 = 8/4, then x=
velikii [3]

Answer:

first cross multiply

2x×4=3×8

8x=24

then, divide both sides by "8" so x could be alone

x=24/8

x=3

i hope this helps, please give me brainliest

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Step-by-step explanation:

3 0
2 years ago
3x + 4y = 12<br> x + 2y = 10
borishaifa [10]

Answer:

x=-8 and y=9

Step-by-step explanation:

rewrite the equations to x+2y=10,3x+4y=12

sub 2y from both sides x+2y-2y=10-2y

substitue x=10-2y in 3x +4y=12

3(-2y+10)+4y=12

distribute

add-30 to both sides

divide both sides by -2

y=9

sustitute 9 for y in -2y+10=x

x=-8

7 0
2 years ago
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