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irina1246 [14]
2 years ago
8

Subtract the following decimals 1. 19.87 - 8.54 2. 7.93 - 2.03 3. 96.6 - 88.5

Mathematics
1 answer:
Lina20 [59]2 years ago
7 0

Answer:

the answer is

1. 11.33

2. 5.9

3. 8.1

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3(7+x to the power of two);x=2
JulijaS [17]

Answer:

33

Step-by-step explanation:

3(7+x^{2}); x=2

=3(7+2^{2})

=3(7+4)

= 33

5 0
2 years ago
(8-2•29) divided by 3
Nesterboy [21]

[(8 - 2 * 29)]/3

Let's solve inside the brackets first.

According to PEMDAS, multiplication gets solved before subtraction so multiply 2 * 29 in the parentheses.

[(8 - 58)]/3

Subtract 58 from 8 in the parentheses.

(-50)/3

Divide -50 by 3.

-16.667 or -16 2/3 is your answer.

4 0
3 years ago
Shaylee is determining if 6 is the solution to the equation.
Mariulka [41]

Answer:

please give me brainlist and follow

Step-by-step explanation:

42 ÷ w = 7 for w = 6. First, Shaylee must substitute ( ) for ( ). To simplify, Shaylee must divide ( ) by ( ) .

4 0
2 years ago
A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2 :
const2013 [10]

Answer:

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.

This means that n = 1067, \pi = \frac{74}{1067} = 0.069

80% confidence level

So \alpha = 0.2, z is the value of Z that has a pvalue of 1 - \frac{0.2}{2} = 0.9, so Z = 1.28.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 - 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.059

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 + 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.079

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

7 0
2 years ago
A warehouse has a height of 8\frac{1}{2}8 2 1 ​ meters, length of 120120 meters, and width of 20\frac{3}{10}20 10 3 ​ meters
vovangra [49]

Answer:

10,353m³

Step-by-step explanation:

<em>We can look for the volume of the warehouse since we are not told what to look for</em>

Volume of the warehouse = length * width * height

Given

Length  = 120m

Width = 20 3/10 = 203/20 m

Height = 8 1/2m = 17/2 m

Volume of the warehouse = 120 * 203/20 * 17/2

Volume of the warehouse = 6 * 203 * 17/2

Volume of the warehouse = 3 * 203 * 17

Volume of the warehouse = 10,353 cubic metres

Hence the volume of the warehouse is 10,353m³

5 0
2 years ago
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