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Alisiya [41]
3 years ago
8

NEED HELP ASAP!!!

Mathematics
1 answer:
Kay [80]3 years ago
6 0
A

sorry if its wrong looks reasonable
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Alja [10]
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3 years ago
Calculate the average rate of change over the interval 2
Morgarella [4.7K]

Answer:

Average rate of change over the interval 2<= x <= 5:

y = 3x + 5:        3

y = 3x^2 + 1:     21

y = 3^x:             78

<u />

Step-by-step explanation:

2<= x <= 5

Average rate of change over the interval 2<= x <= 5:

<u>y = 3x + 5</u>

y(5) = 3(5) + 5 = 20

y(2) = 3(2) + 5 = 11

Average rate of change = (20 - 11)/(5-2) = 9/3 = <u>3</u>

<u />

<u>y = 3x^2 + 1</u>

y(5) = 3(5^2) + 1 = 75 + 1 = 76

y(2) = 3(2^2) + 1= 13

Average rate of change = (76 - 13)/(5-2) = 63/3 = <u>21</u>

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<u>y = 3^x</u>

y(5) = 3^5 = 243

y(2) = 3^2 =9

Average rate of change = (243-9)/(5-2) = 234/3 =<u> 78</u>

8 0
3 years ago
A cone with a diameter of 12 inches has a volume of 640.88 cubic inches. find the height of the cone
BlackZzzverrR [31]

Answer:

The height of the cone is 17\ in

Step-by-step explanation:

we know that

The volume of a cone is equal to

V=\frac{1}{3}\pi r^{2}h

In this problem we have

r=12/2=6\ in ----> the radius is half the diameter

V=640.88\ in^{3}

assume \pi=3.14

substitute the values and solve for h

640.88=\frac{1}{3}(3.14)(6)^{2}h

h=640.88*3/((3.14)(36))=17\ in

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3 years ago
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Answer:

B

Step-by-step explanation:

Find the area of the circle with r = 36/2     Area1 =  π r²

divide Area1 by two since the upper part of the figure is a semi-circle

then finally add and area of the rectangle   Area2 = (18)(36)

Total area = Area 1 + Area 2

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3 years ago
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What is the quotient?
Ivenika [448]

Answer:

436x

Step-by-step explanation:

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