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4 years ago

3X+4Y=-8 -9X-12Y=-10

1 answer:

7 0

X=−4/3y+−8/3
and
x=−4/3y+10/9

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can you give a description of the relationship between the years since the tree was transplanted and its height in inches? if so

LenKa [72]

Answer:

The height of the tree is 18 inches plus 8 inches for each year since the tree was transplanted.

Explanation:

Please, find attached an image with the table that accompanies this question.

1. Pattern

The table is:

Years: 2 4 5 8 9

Height (in.): 34 50 58 82 90

The most simple pattern is a linear pattern. A linear pattern has a constante rate of change.

The rate of change between two points is:

rate of change = change in the output / changee in the input

Find the rate of change for the data:

(50 - 34) in / (4 - 2) year = 16in / 2year = 8in/year

(58 - 50) in / (5 - 4) year = 8in/1year = 8 in/year

(82 - 58) in / (8 - 5) year = 24in / 3year = 8 in/year

(90 - 82) in / (9 - 8) year = 8in / 1 year = 8 in/year

Hence, the heigth and the years since the tree was transplantated show a linear relationship: every year the tree grew 8 inches.

2. Intial height:

You can find the initial height of the tree by using the rate of change of the height.

At year 2: height = 34 inches

At year 1: height = 34 inches - 8 inches = 26 inches

At year 0: height = 26 inches - 8 inches = 18 inches

3. Relationship

You can describe the relationship in terms of the initial height and the numbers of years since the tree was transplantated.

Then, the height of the tree is 18 inches plus 8 inches for each year since the tree was transplanted.

You can even write an equation (function):

name H the height of the tree in inches
name y the number of years since the tree was transplantated

the equation is: H = 18 + y

8 0

4 years ago

7/12-1/3= plz help me

Leto [7]

Answer:

0.25

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Aj is traveling north on a road while Rogan is traveling south on the same road. they pass by each other at 3pm. Aj is traveling

Alina [70]

Recall your d = rt, distance = rate * time.

both folks are traveling in opposite directions, Aj is northbound and Rogan is southbound.

we know Aj is going at a rate of 30mph and Rogan at 40mph, let's say that by the time they are 105 miles apart, Aj has covered "d" miles, then Rogan has covered the slack from 105 and "d", or "105 - d" miles.

let's also keep in mind they they both have been driving the same amount of time, say "t" hours.

$\bf \begin{array}{lcccl}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
Aj&d&30&t\\
Rogan&105-d&40&t
\end{array}
\\\\\\
\begin{cases}
\boxed{d}=30t\\
105-d=40t\\
--------\\
105-\boxed{30t}=40t
\end{cases}
\\\\\\
105=70t\implies \cfrac{105}{70}=t\implies \cfrac{3}{2}=t\implies 1\frac{1}{2}=t$

when they passed each other, it was 3pm, by the time they are both 105 miles apart, they have been traveling for 1½ hours. What time is it? well, is just 4:30pm.

4 0

3 years ago

5 - 3 x = 2 - 6 (X + 2)

STatiana [176]

Answer:

X = -5

Step-by-step explanation:

3 0

3 years ago

A plane lamina with constant density p(x, y) = p occupies a region in the xy-plane bounded by a simple closed path C. Show that

stira [4]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.

8 0

4 years ago