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WARRIOR [948]
3 years ago
10

3X+4Y=-8 -9X-12Y=-10

Mathematics
1 answer:
Yuliya22 [10]3 years ago
7 0
X=<span><span><span><span>−4/</span>3</span>y</span>+<span><span>−8/</span><span>3
and
</span></span></span>x=<span><span><span><span>−4/</span>3</span>y</span>+<span>10/<span>9</span></span></span>
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riadik2000 [5.3K]
Complete the square: 
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Revenue is 3,000,cost of goods is 1,500, selling expense is 500 what is the prophit?
tia_tia [17]
In this situation the revenue is the total sales you make before all expenses.
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Use the graph of the following function (x) to find the value. <br> f(1)
kvv77 [185]

From the graph of the given function , the value of f(1) = -1.

As given in the question,

From the graph of the given function,

Two coordinates from the graph are as follow:

( x₁ , y₁) = (1, -1)

( x₂ , y₂ ) = ( 0, -3 )

Equation of the line representing the function is given by:

(y - y₁) /(x-x₁) = ( y₂ -y₁)/ (x₂ -x₁)

⇒(y +1)/ (x-1) = (-3 +1)/ (0-1)

⇒ (y +1)/ (x-1) = 2

⇒y +1 = 2x -2

⇒ y = 2x -3

To get the value of x we have,

  y = f(x)

⇒f(x) = 2x -3

⇒f(1) = 2(1) -3

⇒f(1) = -1

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11 months ago
(Calculus help, 25 points, will give brainliest) Find the sum of the sigma notation below.
Andreyy89

\displaystyle\sum_{i=3}^{10}(2i-9)=2\sum_{i=3}^{10}i-9\sum_{i=3}^{10}1

Recall that

\displaystyle\sum_{i=1}^n1=n

\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2

Your sums start at i=3, so in order to apply these formulas directly, you need to compensate for the missing first two terms:

\displaystyle\sum_{i=3}^{10}1=\sum_{i=1}^{10}1-(1+1)=10-2=8

\displaystyle\sum_{i=3}^{10}i=\sum_{i=1}^{10}i-(1+2)=\frac{10\cdot11}2-3=52

\implies\displaystyle\sum_{i=3}^{10}(2i-9)=2\cdot52-9\cdot8=\boxed{32}

4 0
2 years ago
What does h equal in the equation S=2πr2+2πrh?
Troyanec [42]

A

Step-by-step explanation:First, subtract

2

π

r

2

from each side of the equation to isolate the

h

term:

S

−

2

π

r

2

=

2

π

r

h

+

2

π

r

2

−

2

π

r

2

S

−

2

π

r

2

=

2

π

r

h

+

0

S

−

2

π

r

2

=

2

π

r

h

Now, divide each side of the equation by

2

π

r

to solve for

h

:

S

−

2

π

r

2

2

π

r

=

2

π

r

h

2

π

r

S

−

2

π

r

2

2

π

r

=

2

π

r

h

2

π

r

S

−

2

π

r

2

2

π

r

=

h

h

=

S

−

2

π

r

2

2

π

r

Or

h

=

S

2

π

r

−

2

π

r

2

2

π

r

h

=

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−

2

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r

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=

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π

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−

r

4 0
3 years ago
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