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Anna [14]
3 years ago
11

Which graph shows a system of equations with the solution (5,-3)?

Mathematics
1 answer:
creativ13 [48]3 years ago
3 0
Bottom right corner
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The extended table is a rectangular with an area of (18+6x) square feet. Write an expression in simplest form that represents th
Tasya [4]
You can take a six out of both factors, 6(3 + x )

so the length would be 6 and the width would be (3+x)
4 0
4 years ago
Write 8256 correct to 3 significant figures
Svet_ta [14]

Answer:

8260

Step-by-step explanation:

the zero will be ignored

3 0
4 years ago
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A moose population is growing exponentially following the pattern in the table shown below. Assuming that the pattern continues,
Alika [10]

The population of the moose after 12 years is 7692

Step-by-step explanation:

The form of the exponential growth function is y=a(b)^{x} , where

  • a is the initial value
  • b is the growth factor

The table:

→  x  :  y

→  0  :  40

→  1   :  62

→  2  :  96

→  3  :  149

→  4  :  231

To find the value of a , b in the equation use the data in the table

∵ At x = 0 , y = 40

- Substitute them in the form of the equation above

∵ 40=a(b)^{0}

- Remember any number to the power of zero is 1 (except 0)

∴ 40 = a(1)

∴ a = 40

- Substitute the value of a in the equation

∴ y=40(b)^{x}

∵ At x = 1 , y = 62

- Substitute them in the form of the equation above

∵ 62=40(b)^{1}

∴ 62 = 40 b

- Divide both sides by 40

∴ 1.55 ≅ b

∴ The growth factor is about 1.55

- Substitute its value in the equation

∴ The equation of the population is y=40(1.55)^{x}

To find the population of moose after 12 years substitute x by 12 in the equation

∵ y=40(1.55)^{12}

∴ y ≅ 7692

The population of the moose after 12 years is 7692

Learn more:

You can learn more about the logarithmic functions in brainly.com/question/11921476

#LearnwithBrainly

7 0
3 years ago
Which graph has the same end behavior as the graph of f(x) = –3x3 – x2 + 1?
Marta_Voda [28]
The answer to the question is D.
3 0
3 years ago
PLEASE HELP!!
Tanya [424]

Answer:

First blank: [-π/2 , π/2]

Second blank: [-π/2 , π/2]

Step-by-step explanation:

The conditions for inverse function to exist is that the function should be one to one function.

A function for which every element of the range of the function corresponds to exactly one element of the domain.

The function can be tested by the vertical line test.

For the given function f(x) = sin x is not one to one function.

so, the domain of the function f(x)=sin x restricted so that its inverse function exists

The domain will be the range provided that when we apply the vertical line test will intersects at only one point

So, the domain will be<u> [-π/2 , π/2]</u>

And this means f(x) = sin⁻¹ x are on the interval<u> [-π/2 , π/2]</u>

3 0
4 years ago
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