The question is asking what v_final is, given that v_initial is at 300 feet. and v_initial is at 0 feet.
We know there will be a constant downward acceleration of 32.15 ft/s^2.
Use the following equation:
v_final^2 = v_initial^2 + 2ah
v_final^2 = (160 ft/s)^2 + 2(-32.15 ft/s^2)(300 ft) = 6310 ft^2/s^2
v_final = (6310 ft^2/s^2)^1/2 = 79.4 ft/s.
Answer:
b=-25
Step-by-step explanation:
10= -2/5b
10= -2/5b
------ -------
-2/5 -2/5b
b=-25
Check:
-2/5(-25)=10
10=10
A dilation would produce<span> a </span>similar figure. Therefore, the sequence of transformations that will produce a similar but not congruent figures would be the first and the third option. Figure TUVWX is dilated by a scale factor of 6 and then rotated 90° counterclockwise around the origin; and f<span>igure TUVWX is reflected across the x-axis and dilated by a scale factor of 7. Hope this answers your question.</span>
The answer is x=11
4x-30=14
You add 30 to each side=4x=44
Then you divide 44 by 4 which=11
Answer:
number 3
Step-by-step explanation:
