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sleet_krkn [62]
3 years ago
6

Maths geometry quadrilateral​

Mathematics
1 answer:
ehidna [41]3 years ago
7 0

Answer:

What’s the question?

Step-by-step explanation:

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Can someone please help me with this problem? You need to find the value of x and y by using the strategy of ELIMINATION. Please
Setler [38]

Answer:

x = 136/35; y = -⁹/₁₀

Step-by-step explanation:

(1)         7x + 8y = 20

(2)        7x – 2y = 29       Subtract (2) from (1)

                  10y =  -9        Divide each side by 10

(3)                 y =  -⁹/₁₀     Substitute (3) into (1)

      7x - 2(-⁹/₁₀) = 29

      7x + 18/10  = 29                       Subtract 18/10 from each side

      7x              =      29 - 18/10

      7x              = (290 - 18)/10

      7x              =          272/10        Divide each side by 7

        x              =           272/70

        x              =           136/35

x = 136/35; y = -⁹/₁₀

Check:

(1) 7(136/35) + 8(-⁹/₁₀) = 20

      136/5    -   72/10 = 20

      136/5    -   36/5  = 20

                      100/5  = 20

                       20      = 20

(2) 7(136/35) – 2(-⁹/₁₀)  = 29

       136/5    +    18/10 = 29

       136/5    +      ⁹/₅    = 29

                        145/5  = 29

                        29       = 29

5 0
3 years ago
Recent census data indicated that 14.2% of adults between the ages of 25 and 34 live with their parents. A random sample of 125
kicyunya [14]

Answer:

The  probability is  P(14 <  X  <  20 ) =  0.5354  

Step-by-step explanation:

From the question we are told that

   The  proportion that live with their parents is  \r p  =  0.142

   The  sample  size is n =  125

   

Given that there are two possible outcomes and that this outcomes are independent of each other then we can say the Recent census data follows a Binomial distribution

  i.e  

       X   \  \~ \ B( \mu ,  \sigma )

Now the mean is evaluated as

      \mu  =  n *  \r p

      \mu  =  125 *  0.142

      \mu  =  17.75

Generally the proportion that are not staying with parents is  

      \r  q  =  1 -  \r  p

= >    \r  q  =  0.858

The standard deviation is mathematically evaluated as

     \sigma  =  \sqrt{n * \r p  *  \r q }

     \sigma  =  \sqrt{ 125 *  0.142 * 0.858  }

    \sigma  = 3.90

Given the n is large  then we can use normal approximation to evaluate the probability as follows  

     P(14 <  X  <  20 ) =  P( \frac{ 14 -  17.75}{3.90}

Now applying continuity correction

      P(14 <  X  <  20 ) =  P( \frac{ 13.5 -  17.75}{3.90}  < \frac{  X  - \mu }{\sigma } < \frac{ 19.5 -  17.75}{3.90}   )

Generally  

    \frac{  X  - \mu }{\sigma }  =  Z  ( The  \ standardized \ value  \  of  X )

    P(14 <  X  <  20 ) =  P( \frac{ 13.5 -  17.75}{3.90}  < Z< \frac{ 19.5 -  17.75}{3.90}   )

     P(14 <  X  <  20 ) =  P( -1.0897   < Z<  0.449 }   )

    P(14 <  X  <  20 ) =   P( Z<  0.449   ) - P(Z  <   -1.0897)

So  for the z -  table  

         P( Z<  0.449   ) =  0.67328

         P(Z  <   -1.0897)  = 0.13792

 P(14 <  X  <  20 ) =   0.67328 -  0.13792    

  P(14 <  X  <  20 ) =  0.5354  

     

6 0
3 years ago
Show that (a+b)^2=4p^2​
Alja [10]

LHS :-

  • ( a + b)²
  • (P + q + P - q)²
  • (2p)²
  • 2²p²
  • 4p² = RHS
8 0
2 years ago
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