<span>B. {x|–5 < x < 6} and</span>C. (–5, 6)
Find the rate at which you work, that is, the # of walls painted per hour:
13 1/3 walls 40/3
------------------ = ---------- wall per hour
14 1/4 hr 57/4
Keep 40/3 as it is; invert the divisor (57/4) and then multiply the result by 40/3:
40 4 160 wall
------ * ------ = --------------- = approx. 0.94 wall in one hour, or 160/171 wall / hr
3 57 171 hr
936 <span>39 </span>= 24
24 = 240 to the nearest tenth
24 = 24 to the nearest hundredth
24 = 24 to the nearest thousandth
= 0 to the nearest tenth
= 0 to the nearest hundredth
= 0 to the nearest thousandth
Answer:
Step-by-step explanation:
<u>Equation Solving</u>
We are given the equation:
It's required to solve the equation for D. All letters must preserve their capitalization.
We must isolate the letter D by removing from the left side all the terms and coefficients that surround it.
Adding 7:
Dividing by f:
The top row of matrix A (1, 2, 1) is multiplied with the first column of matrix B (1,0,-1) and the result is 1x1 + 2x0 + 1x -1 = 0 this is row 1 column 1 of the resultant matrix
The top row of matrix A (1,2,1) is multiplied with the second column of matrix B (-1, -1, 1) and the result is 1 x-1 + 2 x -1 + 1 x 1 = -2 , this is row 1 column 2 of the resultant matrix
Repeat with the second row of matrix A (-1,-1.-2) x (1,0,-1) = 1 this is row 2 column 1 of the resultant matrix, multiply the second row of A (-1,-1,-2) x (-1,-1,1) = 0, this is row 2 column 2 of the resultant
Repeat with the third row of matrix A( -1,1,-2) x (1,0, -1) = 1, this is row 3 column 1 of the resultant
the third row of A (-1,1,-2) x( -1,-1,1) = -2, this is row 3 column 2 of the resultant matrix
Matrix AB ( 0,-2/1,0/1,-2)
