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2 years ago

8

Jason needs to run 30 laps before basketball practice. His coach makes a deal with the team that on Friday’s they only need to c

omplete 5/6 of that.
Write an expression or equation to represent the number of laps to complete on Friday.

1 answer:

leva [86]2 years ago

5 0

Answer:

a little bit less than 30

Step-by-step explanation:

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Please help, basic Algebra question

Tju [1.3M]

Answer:

The given expression $(\frac{5}{6} a^{9}p^{5}) ^{3} = \frac{125}{216} \times a^{(27) } \times p^{(15)}$

Step-by-step explanation:

Here, the given expression is: $(\frac{5}{6} a^{9}p^{5}) ^{3}$

Now, starting from the outer most bracket.

As we know :

$(abc)^{n} = (a)^{n} \times (b)^{n} \times (c)^{n}$

and $(a^m)^{n} = a^{(m \times n)}$

⇒ $(\frac{5}{6} a^{9}p^{5}) ^{3} = (\frac{5}{6})^{3} \times (a^{9})^{3} \times (p^{5}) ^{3}\\$

$=\frac{125}{216} \times (a)^{(9\times3) } \times (p)^{(5 \times 3)}\\= \frac{125}{216} \times a^{(27) } \times p^{(15)}$

Hence, the given expression $(\frac{5}{6} a^{9}p^{5}) ^{3} = \frac{125}{216} \times a^{(27) } \times p^{(15)}$

7 0

2 years ago

Read 2 more answers

Can some one explain in an easy way pls

Helga [31]

What needs to be done first is to add up females and males that have passed.

42 + 14 = 56

so out of 56 students who passed 42 females passed 42/56 = 3/4 = 0.75

out of 56 students who passed, 14 males passed which turns into 14/56 = 1/4 = 0.25

check work; 0.75 + 0.25 = 1.00

NOW WE ARE DOING FAILS.

15 + 5 = 20

so out of 20 students who failed, 15 females failed so it turns into 15/20 = 3/4 = 0.75

out of 20 students who failed, 5 males failed. 5/20 = 1/4 = 0.25

check work; 0.75 + 0.25 = 1.00

i hope this helped! :)

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2 years ago

Given f(x) = x − 7 and g(x) = x2 . Find g(f(−1)).

ivann1987 [24]

Answer:

64

Step-by-step explanation:

$g(f(-1))$ can be found by first finding $f(-1)$ then taking that result and putting it into the function $g$ .

$f(-1)$ means we are going to take the expression $x-7$ and evaluate it for $x=-1$ :

$-1-7$

$-8$

So $f(-1)=-8$ .

So we have this so far:

$g(f(-1))=g(-8)=(-8)^2=64$ .

$g(-8)$ was found by replacing $x$ in $x^2$ with $-8$ .

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