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Crank
3 years ago
14

What's the average between 63 and 162

Mathematics
1 answer:
fgiga [73]3 years ago
7 0

Answer:

112.5

Step-by-step explanation:

The average is calculated as

average = \frac{sum}{count}, then

average = \frac{63+162}{2} = \frac{225}{2} = 112.5

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2. If y varies inversely as x and<br> y = 3 when x = 5, find x when y = 2.5
4vir4ik [10]

Answer:

Step-by-step explanation:

From the law of variation,

y <> 1/x, where <> is the constant of proportionality. Therefore

y = k/x where k is a constant

3 = k/5 and k = 15

To find x when y = 2.5(5/2)

Go back to the second equation

y = k/x

5/2 = 15/x

When you cross multiply

5x = 30.

Divide through by 5,

x = 6.

8 0
4 years ago
Steve makes a banner with an area of 8 square feet. On a grid, draw all possible rectangles with an area of 8 square feet and si
Maksim231197 [3]

Answer:

The correct answers are with side lengths 1 feet and 8 feet, the perimeter is 18 feet; and with side lengths 2 feet and 4 feet, the perimeter is 12 feet.

Step-by-step explanation:

The area of a rectangular banner is 8 square feet.

The side lengths of this rectangular banner are whole numbers.

Thus the possible pairs of side lengths that would give 8 when multiplied with each other are (1 , 8) ; (2 , 4).

So the possible side lengths are 1 feet and 8 feet or 2 feet and 4 feet.

The perimeter when the side lengths are 1 feet and 8 feet are 18 feet.

The perimeter when the side lengths are 2 feet and 4 feet are 12 feet.

8 0
3 years ago
Read 2 more answers
53/7 as a mixed number
marysya [2.9K]
Its already an improper fraction.
If you mean mixed number it would be 7 4/7.
Hope this helps!:)
7 0
3 years ago
Read 2 more answers
Two equiangular decagons are congruent.<br> Sometimes/Always/Never
OLga [1]

Answer:

Two equiangular decagons are sometimes congruent.

4 0
3 years ago
On a single roll of a pair of dice, what are the odds against rolling a sum of 12?
o-na [289]

Answer:

\frac{1}{35}

Step-by-step explanation:

On a single roll of a pair of dice. When a pair of dice are rolled the possible outcomes are as follows:

(1,1)         (1,2)          (1,3)  (1,4)  (1,5)  (1,6)

(2,1)  (2,2)  (2,3)  (2,4)  (2,5)  (2,6)

(3,1)  (3,2)  (3,3)  (3,4)  (3,5)  (3,6)

(4,1)  (4,2)  (4,3)  (4,4)  (4,5)  (4,6)

(5,1)  (5,2)  (5,3)  (5,4)  (5,5)  (5,6)

(6,1)  (6,2)  (6,3)  (6,4)  (6,5)  (6,6)

The number of outcomes that gives us 12 are (6,6). There is only one outcome that gives us sum 12.

Total outcomes = 36

Odd against favor = \frac{non \ favorable\ outcomes}{favorable \ outcomes}

Number of outcomes of getting sum 12 is 1

Number of outcomes of not getting sum 12 is 36-1= 35

odds against rolling a sum of 12= \frac{1}{35}

3 0
3 years ago
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