Answer:
The answer is below
Step-by-step explanation:
The question is not complete. A complete question is in the form:
A letter is chosen at random from the letters of the word EXCELLENT. Find the probability that letter chosen is i) a vowel ii) a consonant.
Solution:
The total number of letters found in the word EXCELLENT = 9
i) The number of vowel letters found in the word EXCELLENT = {E, E, E} = 3
Hence, probability that letter chosen is a vowel = number of vowels / total number of letters = 3 / 9 = 1 / 3
probability that letter chosen is a vowel = 1/3 = 0.333 = 33.3%
ii) The number of consonant letters found in the word EXCELLENT = {X, C, L, L, N, T} = 6
Hence, probability that letter chosen is a consonant = number of consonant / total number of letters = 6 / 9 = 2 / 3
probability that letter chosen is a consonant = 2/3 = 0.667 = 66.7%
The answer depends on the way you solved it.
I am assuming you take the base on which you perceived to be: . 5 and height which is 2.
So you must've ended with 1
But in actuality, you need to use the equation above and plug in 1.5 and 1
Subtract them and you should get 1.25
Do the same to the other side, you should get 6.
.125 x 6 = .875
Where's the picture???? I'm confusedd
Answer:
A and E
Step-by-step explanation:
9^3 / 9^3
Same number on top and bottom so 1 is an answer
look at the exponents, when dividing with exponents, you just subtract them, so it could also be 9^0, which is also 1
Answer:
x = 26, y = 9
Step-by-step explanation:
Add the bottom equations and set them equal to 180
8x -28 = 180
8x = 208 divide each by 8
x = 26
Find the bottom right, 3(26) - 11
78 - 11 = 67
The unlabeled top left box is also equal to 67 degrees.
So 2y + 5 = 23
2y = 18
y = 9
