It is (0,0) there ya go :)
Answer:
The common difference is -5/4
T(n) = T(0) - 5n/4,
where T(0) can be any number. d = -5/4
Assuming T(0) = 0, then first term
T(1) = 0 -5/4 = -5/4
Step-by-step explanation:
T(n) = T(0) + n*d
Let
S1 = T(x) + T(x+1) + T(x+2) + T(x+3) = 4*T(0) + (x + x+1 + x+2 + x+3)d = 240
S2 = T(x+4) + T(x+5) + T(x+6) + T(x+7) = 4*T(0) + (x+5 + x+6 + x+7 + x+8)d = 220
S2 - S1
= 4*T(0) + (x+5 + x+6 + x+7 + x+8)d - (4*T(0) + (x+1 + x+2 + x+3 + x+4)d)
= (5+6+7+8 - 1 -2-3-4)d
= 4(4)d
= 16d
Since S2=220, S1 = 240
220-240 = 16d
d = -20/16 = -5/4
Since T(0) has not been defined, it could be any number.
Answer:
Step-by-step explanation: I would say y=x+2 or 2 because every number that you add 2 to, it gives you the solution which is the second number
Hope this helps!!!!
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Answer:
$138,345
Step-by-step explanation:
This is a compound decline problem, which will be solve by the compound formula:
Where
F is the future value (value of house at 2030, 14 years from 2016)
P is the present value ($245,000)
r is the rate of decline, in decimal (r = 4% = 4/100 = 0.04)
t is the time in years (2016 to 2030 is 14 years, so t = 14)
We substitute the known values and find F:
Rounding it up, it will be worth around $138,345 at 2030
