Answer:
its 34
Step-by-step explanation:
Triangle QST is similar to triangle PQR
We are given that measure of angle SRP is 90°
Q is the point of the hypotenuse SP
Segment QR is perpendicular to PS and T is a point outside the triangle on the left of s
We need to find which triangle is similar to triangle PQR
So,
Using Angle - Angle - Angle Criterion We can say that
m∠PQR = m∠SQR (AAA similarity)
m∠SQR=m∠SQT (AAA similarity)
Where m∠Q =90° in ΔQST and PQR
Therefore ΔQST is similar to ΔPQR
Learn more about similarity of triangles here
brainly.com/question/24184322
#SPJ4
Answer:

Explanation:
Assuming the correct expression is to find the following limit:

Use the property the limit of the quotient is the quotient of the limits:

Evaluate the numerator:

Evaluate the denominator:
- Since


Answer:
LOL OK
Step-by-step explanation:
HAHAHAHAHAHAHAHAHAHAHAHA
Answer:
10.12
Step-by-step explanation:
5.6x2