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Marizza181 [45]

3 years ago

9

Deborah finds that that the theoretical probability of flipping "heads" on a fair coin was 50%. After she flipped the fair coin

100 times, she calculated that she flipped heads 45 times. what is the percent difference in theoretical and experimental probability

1 answer:

nydimaria [60]3 years ago

7 0

Answer: 5% if it’s bubble sheet then 0.05

Step-by-step explanation:

Probability of flipping heads=50%

Probability of flipping practically = 45/100

=45

So 50%-45% = 5%

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Help solving this problem

amid [387]

2t + 5b = 20
8t + 3b = 29
Multiply the first equation by-4
-8t -20b = -80
8t + 3b = 29
-17b = -51
b = 3
Plug 3 in for b into either equation and solve for t.
2t + 5(3) = 20
2t + 15 = 20
2t = 5
Divide both sides by 2
t = 2.50

5 0

3 years ago

How many bases are there in the triangular pyramid shown below?

sukhopar [10]

Answer:

1

Step-by-step explanation:

5 0

3 years ago

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A cardboard box without a lid is to have a volume of 19,652 cm3. Find the dimensions that minimize the amount of cardboard used.

Effectus [21]

Answer:

The dimension of the cardboard is 34 cm by 34 cm by 17 cm.

Step-by-step explanation:

Let the dimension of the cardboard box be x cm by y cm by z cm.

The surface area of the cardboard box without lid is

f(x,y,z)= xy+2xz+2yz.....(1)

Given that the volume of the cardboard is 19,652 cm³.

Therefore xyz =19,652

$\Rightarrow z=\frac{19652}{xy}$ ......(2)

putting the value of z in the equation (1)

$f(x,y)=xy+2x(\frac{19652}{xy})+2y(\frac{19652}{xy})$

$\Rightarrow f(x,y)=xy+\frac{39304}{y})+\frac{39304}{x}$

The partial derivatives are

$f_x=y-\frac{39304}{x^2}$

$f_y=x-\frac{39304}{y^2}$

To find the dimension of the box set the partial derivatives $f_x=0$ and $f_y=0$ .Therefore $y-\frac{39304}{x^2}=0$

$\Rightarrow y=\frac{39304}{x^2}$ .......(3)

and $x-\frac{39304}{y^2}=0$

$\Rightarrow x=\frac{39304}{y^2}$ .......(4)

Now putting the x in equation (3)

$y =\frac {39304}{(\frac{39304}{y^2})^2}$

$\Rightarrow y=\frac{y^4}{39304}$

$\Rightarrow y^3= 39304$

⇒y=34 cm

Then $\Rightarrow x=\frac{39304}{34^2}$ =34 cm.

Putting the value of x and y in the equation (2)

$z=\frac{19652}{34 \times 24}$

=17 cm.

The dimension of the cardboard is 34 cm by 34 cm by 17 cm.

4 0

3 years ago

Round each number to the nearest ten 24. 311. 107

astraxan [27]

Answer:

24-20 311-310 107-110

Step-by-step explanation:

3 0

3 years ago

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Previously, an organization reported that teenagers spent 4.5 hours per week, on average, on the phone. The organization thinks

Fudgin [204]

Answer:

The teenagers spent 4.5 hours per week, on average, on the phone.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 4.5

Sample mean, $\bar{x}$ = 4.75

Sample size, n = 15

Alpha, α = 0.05

Sample standard deviation, s = 2

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 4.5\text{ hours per week}\\H_A: \mu > 4.5\text{ hours per week}$

We use one-tailed(right) t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{4.75 - 4.5}{\frac{2}{\sqrt{15}} } = 0.4841$

Now,

$t_{critical} \text{ at 0.05 level of significance, 14 degree of freedom } = 1.76$

Since,

$t_{stat} < t_{critical}$

We accept the null hypothesis. Thus, the teenagers spent 4.5 hours per week, on average, on the phone. The sample contradicted the organization's claim.

7 0

4 years ago