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Romashka-Z-Leto [24]
3 years ago
15

What is 24/4 as a whole number

Mathematics
1 answer:
stiks02 [169]3 years ago
7 0
4 fits into 24 6 times so 24/4 written as a whole number is 6! I hope this helped :D
You might be interested in
How many distinguishable permutation are possible with all the letters of the word sequence​
Marizza181 [45]

Step-by-step explanation:

hey, hope this helps/ is right :))

8 0
3 years ago
The side of one square is equal to 3m and its diagonal is equal to the side of a second square. Find the diagonal of the second
navik [9.2K]

Answer:

6m

Step-by-step explanation:

the side of first square = 3 m

area of first square = 3^2= 9 m^2

let the side of second square = x m

since diagonal of first square = x m as per the question

in a square each angle is 90 degree

therefore by applying pythagorus theorem ,

diagonal ^2 = side^2 + side ^2

diagonal^2 = 3^2+3^2=9+9

DIAGONAL= square root of 18

diagonal= 3\sqrt{2} m = side of second square

therefore in second square ,

one angle is 90  degree , therefore by applying pythagorue theorem

diaqonal^2 = side ^2 + side ^2 = (3\sqrt{2})^2 + ( 3\sqrt{2})^2

diagonal ^2 = 18 + 18

diagonal = square root of 36

therefore diagonal of second square is 6m

hope it helps you... please mark me as the brainliest..

8 0
3 years ago
Read 2 more answers
I have an assignment and I am having trouble with it. Can someone please help ASAP???
bezimeni [28]

Answer:

A) Find the sketch in attachment.

In the sketch, we have plotted:

- The length of the arena on the x-axis (90 feet)

- The width of the arena on the y-axis (95 feet)

- The position of the robot at t = 2 sec (10,30) and its position at t = 8 sec (40,75)

The origin (0,0) is the southweast corner of the arena. The system of inequalities to descibe the region of the arena is:

0\leq  x \leq 90\\0\leq y \leq 95

B)

Since the speed of the robot is constant, it covers equal distances (both in the x- and y- axis) in the same time.

Let's look at the x-axis: the robot has covered 10 ft in 2 s and 40 ft in 8 s. There is a direct proportionality between the two variables, x and t:

\frac{10}{2}=\frac{40}{8}

So, this means that at t = 0, the value of x is zero as well.

Also, we notice that the value of y increases by \frac{75-30}{8-2}=7.5 ft/s (7.5 feet every second), so the initial value of y at t = 0 is:

y(t=0)=30-7.5\cdot 2 =15 ft

So, the initial position of the robot was (0,15) (15 feet above the southwest corner)

C)

The speed of the robot is given by

v=\frac{d}{t}

where d is the distance covered in the time interval t.

The distance covered is the one between the two points (10,30) and (40,75), so it is

d=\sqrt{(40-10)^2+(75-30)^2}=54 ft

While the time elapsed is

t=8 sec-2 sec = 6 s

Therefore the speed is

v=\frac{54}{6}=9 ft/s

D)

The equation for the line of the robot is:

y=mx+q

where m is the slope and q is the y-intercept.

The slope of the line is given by:

m=\frac{75-30}{40-10}=1.5

Which means that we can write an equation for the line as

y=mx+q\\y=1.5x+q

where q is the y-intercept. Substituting the point (10,30), we find the value of q:

q=y-1.5x=30-1.5\cdot 10=15

So, the equation of the line is

y=1.5x+15

E)

By prolonging the line above (40,75), we see that the line will hit the north wall. The point at which this happens is the intersection between the lines

y=1.5x+15

and the north wall, which has equation

y=95

By equating the two lines, we find:

1.5x+15=95\\1.5x=80\\x=\frac{80}{15}=53.3 ft

So the coordinates of impact are (53.3, 95).

F)

The distance covered between the time of impact and the initial moment is the distance between the two points, so:

d=\sqrt{(53.5-0)^2+(95-15)^2}=95.7 ft

From part B), we said that the y-coordinate of the robot increases by 15 feet/second.

We also know that the y-position at t = 0 is 15 feet.

This means that the y-position at time t is given by equation:

y(t)=15+7.5t

The time of impact is the time t for which

y = 95 ft

Substituting into the equation and solving for t, we find:

95=15+7.5t\\7.5t=80\\t=10.7 s

G)

The path followed by the robot is sketched in the second graph.

As the robot hits the north wall (at the point (53.3,95), as calculated previously), then it continues perpendicular to the wall, this means along a direction parallel to the y-axis until it hits the south wall.

As we can see from the sketch, the x-coordinate has not changed (53,3), while the y-coordinate is now zero: so, the robot hits the south wall at the point

(53.3, 0)

H)

The perimeter of the triangle is given by the sum of the length of the three sides.

- The length of 1st side was calculated in part F: d_1 = 95.7 ft

- The length of the 2nd side is equal to the width of the arena: d_2=95 ft

- The length of the 3rd side is the distance between the points (0,15) and (53.3,0):

d_3=\sqrt{(0-53.3)^2+(15-0)^2}=55.4 ft

So the perimeter is

d=d_1+d_2+d_3=95.7+95+55.4=246.1 ft

I)

The area of the triangle is given by:

A=\frac{1}{2}bh

where:

b=53.5 ft is the base (the distance between the origin (0,0) and the point (53.3,0)

h=95 ft is the height (the length of the 2nd side)

Therefore, the area is:

A=\frac{1}{2}(53.5)(95)=2541.3 ft^2

J)

The percentage of balls lying within the area of the triangle traced by the robot is proportional to the fraction of the area of the triangle with respect to the total area of the arena, so it is given by:

p=\frac{A}{A'}\cdot 100

where:

A=2541.3 ft^2 is the area of the triangle

A'=90\cdot 95 =8550 ft^2 is the total area of the arena

Therefore substituting, we find:

p=\frac{2541.3}{8550}\cdot 100 =29.7\%

4 0
3 years ago
QRST is a rectangle. Find the length of the diagonals.<br><br> QS=8x−11 and RT=4x+21
valkas [14]

Answer: they’re both 53

Step-by-step explanation:

i just took the test and it is correct

7 0
2 years ago
A right angle has a league of 13 cm in the hypotenuse of 21 cm what is the length of the other leg
natta225 [31]
You can use c^2 = a^2 + b^2 to solve for the length of the other leg. Just substitute the values to the variable then transpose to get the value of the missing variable.

Given: a = 13; c = 21
Required: b - other leg
Solution:
   c^2 = a^2 + b^2
 21^2 = 13^2 + b^2
   441 = 169 + b^2
  b^2 = 272
  <span>√b = 16.49
    b = 16.49 cm</span>
8 0
3 years ago
Read 2 more answers
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