Answer:
I hope this helps :D
Step-by-step explanation:
4
It can be done a lot easier: instead of calculating the probability of one head, two heads, three heads, ... one just needs to calculate the probability of no heads: that is simply 0.5
0.5
n
. If you subtract it from 1, you get the probability you want: it's because that's the chance of not no heads, meaning at least one head. So, the formula is: 1−0.5
1
−
0.5
n
More formally: if X is throwing at least one head,
()=1−(¬)
P
(
X
)
=
1
−
P
(
¬
X
)
, where ¬
¬
X
is throwing zero heads.
