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4vir4ik [10]
3 years ago
11

Consider the following cost function.

Mathematics
1 answer:
Makovka662 [10]3 years ago
4 0

Answer:

a)Average cost function =\bar{C(x)}=\frac{1000+0.1x}{x}

Marginal cost function =C'x=0.1

b) \bar{C(2000)}=0.6

C'(2000)=0.1

c)\bar{C(2000)}=0.6 is the average cost to produce first 2000 items

C'(2000)=0.1 is the marginal cost to produce 2001 th item

Step-by-step explanation:

Cost function: C(x) = 1000 + 0.1x

a)Find the average cost and marginal cost functions.

Average cost function =\bar{C(x)}=\frac{C(x)}{x}

Average cost function =\bar{C(x)}=\frac{1000+0.1x}{x}

Marginal cost function =C'x=0.1

b) Determine the average and marginal cost when x = a.

a = 2000

Average cost function =\bar{C(x)}=\frac{1000+0.1x}{x}=\frac{1000+0.1a}{a}=\frac{1000+0.1(2000)}{2000}=0.6

So, \bar{C(2000)}=0.6

Marginal cost function =C'(2000)=0.1

c)Interpret the values obtained in part​ (b).

\bar{C(2000)}=0.6 is the average cost to produce first 2000 items

C'(2000)=0.1 is the marginal cost to produce 2001 th item

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Natalka [10]

Answer:

y=x−3

Step-by-step explanation:

Flip the equation.

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Add -7 to both sides.

4y+7+−7=4x−5+−7

4y=4x−12

Divide both sides by 4.

\frac{4y}{4}= \frac{4x-12}{4}

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ik this doesnt make any sense but hope this helps :/

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3 years ago
What is the function that defines the following sequence? 10, 12, 14, 16, 18…
Furkat [3]

The sequence shown is defined by a function that generates <em>even</em> numbers equal or greater than 10, defined by the function s = 10 + 2 · (n - 1).

<h3>How to define the function behind a sequence</h3>

Sequences are sets of elements characterized by at least a rule. In this case, the sequence shown is characterized by a function that generates even numbers equal or greater than 10. The function behind the sequence is shown below:

s = 10 + 2 · (n - 1)     (1)

Where n is the <em>element</em> index.

The sequence shown is defined by a function that generates <em>even</em> numbers equal or greater than 10, defined by the function s = 10 + 2 · (n - 1).

To learn more on sequences: brainly.com/question/21961097

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4 0
2 years ago
Show another way to write 100 more than 623 ​
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There are many ways, but here is one:

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Since ‘x’ is 100 and we want 100 more, we just need to add ‘x’ to 623

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4 0
3 years ago
If you shift the exponential parent function, f(x) = 2^x , right 2 units, what is the equation of the new function?
aev [14]

Answer:

g(x)=2^{x-2}

Step-by-step explanation:

<u>Translations</u>

For a > 0

f(x+a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units left}

f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}

f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}

f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}

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6 0
2 years ago
Read 2 more answers
he probability that the San Jose Sharks will win any given game is 0.3694 based on a 13-year win history of 382 wins out of 1034
garri49 [273]

Answer:

0.0071 = 0.71% probability that the San Jose Sharks win 9 games in the upcoming month.

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the Sharks win, or they do not. The probability of the Sharks winning a game is independent of any other game. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that the San Jose Sharks will win any given game is 0.3694.

This means that p = 0.3694

An upcoming monthly schedule contains 12 games.

This means that n = 12

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P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{12,9}.(0.3694)^{9}.(0.6306)^{3} = 0.0071

0.0071 = 0.71% probability that the San Jose Sharks win 9 games in the upcoming month.

6 0
3 years ago
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