Please help with this math question please!!

Use the drop-down menus to complete the statements to match the information shown by the graph

Tresset [83]

Answer:what are answer choices

Step-by-step explanation:

4 0

2 years ago

Junior's brother is 1 1/2

AlladinOne [14]

Answer:

Step-by-step explanation:

1 1/5 of 1 1/2 meters

= (1+1/5) x (1+1/2)

= 1x1 + 1x1/2 + 1x1/5 + 1/5*1/2

= 1 + 1/2 + 1/5 + 1/10

= 1 + (1x5+1x2+1)/10

= 1 8/10

= 1 4/5 meters

6 0

3 years ago

Scott is playing a game in which he rolls a number cube with faces numbered 1through 6 and spins the spinner shown below one tim

defon

Solution:

The total number of possiblities rolling a number cube with faces numbered 1 to 6 is;

And the total number of possibilities spining the spinner is;

The number of possibility where outcome on the cube is greater than 2 is;

$4$

And the number on the spinner less than 9 is;

$2$

Hence, the unique combination is;

$4\times2=8$

CORRECT OPTION: A

7 0

1 year ago

Please help me out with these no one is helping me.<br>Please anyone <br>

Olin [163]

Answer:

Below.

Step-by-step explanation:

You find the values of y by substituting the values of x in the expression x^2 + 3x - 1.

So f(-4) = (-4)^2 + 3(-4) - 1 = 16-12-1 = 3

in the same way f(-3) = -1, f(-2) = -3, f(-1) = -3,

f(0) = -1 and f(1) = 3.

Now plot the points (-4, 3) , (-3, -1) and so on

Then you can read the values off this graph.

8 0

3 years ago

Read 2 more answers

What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$

- Using the Difference of squares formula ( $a^2-b^2=(a+b)(a-b)$ ) we can simplify the denominator of the right side of the equation:

$\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}$

- Multiply both sides of the equation by $(m+3)(3-m)$ and simplify:

$\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}$

- Multiply both sides by $m-3$ :

$(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)$

- Apply Distributive property and simplify:

$(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0$

- Divide both sides of the equation by -6:

$\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0$

- Factor the equation and solve for "m":

$(m-3)^2=0\\\\m=3$

In order to verify it, you must substitute $m=3$ into the equation and solve it:

$\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}$

<em>NO SOLUTION</em>

7 0

3 years ago