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labwork [276]
3 years ago
13

I NEED HELP PLEASE!! PLEASE IM BEGGING YOU!!

Mathematics
1 answer:
Gennadij [26K]3 years ago
7 0
A.) r=C/2(pi)
b.) 6.0
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The table compares the daily average temperature in a park (in degrees Celsius) and the number of people who visited the park th
Simora [160]

Answer:

YES, the number of people who visited the park can be represented as a function of the daily average temperature.

Step-by-step explanation:

From the table of values given which defines the number of visitors to the park as a function of daily temperature, the temperature is the domain values (independent variable), while the number of visitors is the range values (dependent variable).

For any relation to be considered a function, as a principle, any given domain value must have exactly one range value. In other words, there must not be two different range values assign to one domain value.

This means, for the relation between temperature and number of visitors to be considered a function, it must not have a domain value that is mapped to more than one range value.

Examining the table given, if we map each domain value to the range value, we will find out that there are only 1 exact range value for a domain value.

<em>Therefore, we can say: YES, the number of people who visited the park can be represented as a function of the daily average temperature.</em>

7 0
3 years ago
Read 2 more answers
A rectangle has a perimeter of 6 feet.
pickupchik [31]
The answer is “A” and C
4 0
3 years ago
Read 2 more answers
Can someone help me with this please? I will mark you brainliest
lina2011 [118]

Answer:

On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.vvOn the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.vcOn the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.

Step-by-step explanation:

6 0
2 years ago
Dream borrowed $500 at an interest rate of 8%. At the end of the loan period, she had to pay back $530. How long was the loan fo
Aliun [14]

Answer:

The loan was for 9 months only

Step-by-step explanation:

In this question, we are concerned with calculating the time taken for a loan om an interest to be paid back

To calculate this, we use the simple interest formula

Mathematically;

I = PRT/100

where P is the principal which is the amount borrowed and that is $500 according to the question

R is the rate which is 8% according to the question

Interest can be calculated by subtracting the principal from the  amount paid back = 530-500 = 30$

We now plug these values into the equation

30 = (500 × 8× T)/100

100 × 30 = 4000T

T = 3000/4000

T = 0.75 (same as 0.75 × 12 months = 9 months)

5 0
3 years ago
A ski resort claims that there is a 75% chance of snow on any given day in january and that snowfall happens independently from
lys-0071 [83]

Using the binomial distribution, it is found that the mean and the standard deviation of variable x are given as follows:

\mu = 3, \sigma = 0.87

<h3>What is the binomial probability distribution?</h3>

It is the probability of exactly <u>x successes on n repeated trials, with p probability</u> of a success on each trial.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

In this problem, we have that the parameters are given as follows:

n = 4, p = 0.75.

Hence the mean and the standard deviation are given as follows:

  • E(X) = np = 4 x 0.75 = 3.
  • \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{4 \times 0.75 \times 0.25} = 0.87

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

7 0
1 year ago
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