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Kipish [7]
3 years ago
5

Show your working for the following questions:

Mathematics
1 answer:
Llana [10]3 years ago
4 0
\frac{-18}{-3} (divide 3 from numerator and denominator) = \frac{6}{1} = 6

\frac{2}{7} × \frac{8}{3} = \frac{16}{21}

\frac{3}{8} +  \frac{1}{12} =  \frac{9}{24} +  \frac{2}{24} =  \frac{11}{24}
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Help Asap will give brainliest if you start answering by 21 minutes
Elza [17]

<u>Answer:</u>

f(x) = (2x + 1)(2x − 1)

Explanation:

As we can see from the above function f(x) = 4x^{2} − 1, we need to find x-intercept, i.e., the value of x where this function's value is zero.

So let us Equate the function with zero

4x^{2} - 1 = 0 => 4x^{2} = 1 => x^{2} = 1/4 => x = \sqrt{1/4}

Hence we get 2 values of x, i.e., +1/2, and -1/2.

So now we need to check out the functions which are zero at this values of x, so let us substitute values of x in each and every option and see the values of functions.

Option A - f(x) = (4x + 1)(4x − 1) = 3, -3

Option B - f(x) = (2x + 1)(2x − 1)  = 0

Option C - f(x) = 4(x2 + 1)  = 5

Option D - f(x) = 2(x2 − 1) = -3/2

Hence answer is Option B

8 0
3 years ago
At a certain non-profit organization, 51% of employees are college graduates and 47% of employees have more than ten years of ex
Lady bird [3.3K]

Answer: 0.21

Step-by-step explanation:

Let A denotes the event that employees are college graduates.

B denotes that the event that employees have more than ten years of experience.

As per given , we have

P(A)=0.51

P(B)=0.47

P(A∪B)=0.77

We know that , P(A\cup B)=P(A)+P(B)-P(A\cap B)

0.77=0.51+0.47-P(A\cap B)

P(A\cap B)=0.51+0.47-0.77=0.21

Hence, the probability that a randomly selected employee will have more than ten years of experience and be a college graduate = 0.21

8 0
3 years ago
The average amount parents and children spent per child on back-to-school clothes in Autumn 2010 was $527. Assume the standard d
Ad libitum [116K]

Answer: a. 0.14085

b. 3.826 x 10^{-3}

c.  0.5437

d. 0.0811  

Step-by-step explanation:

Given average amount parents and children spent per child on back-to-school clothes in Autumn 2010 , \mu = $527

Given standard deviation , \sigma = $160

Let X = amount spent on a randomly selected child

Also Z = \frac{X-\mu}{\sigma}

a. Probability(X>$700) = P(\frac{X-\mu}{\sigma} > \frac{700-527}{160}) = P(Z>1.08125) = 0.14085 {Using Z % table}

b. P(X<100) = P( Z < \frac{100-527}{160}) = P(Z< -2.66875) = P(Z > 2.66875) = 3.826 x 10^{-3}

c. P(450<X<700) = P(X<700) - P(X<=450)

   P(X<700) = 1 - P(X>=700) = 1 - 0.14085 = 0.8592

   P(X<=450) = P(Z<= \frac{450-527}{160}) = P(Z<= -0.48125) = P(Z<=0.48125) = 0.3155

   So final   P(450<X<700) =  0.8592 - 0.3155 = 0.5437

d. P(X<=300) = P(Z<= \frac{300-527}{160}) = P(Z<= -1.4188) = P(Z>=1.4188) = 0.0811                                                                        

All the above probabilities are calculated using Z % table along with interpolation between two values.

7 0
3 years ago
If (8^9)p = 8^16 what's the value of p?
monitta

Answer:

p  = {8}^{7}

Step-by-step explanation:

(8^9)p = 8^{16 } \\  \\ p =  \frac{8^{16 } }{8^{9 } }  \\  \\  p =  {8}^{16 - 9}  \\  \\  \huge \red{ \boxed{p  = {8}^{7} }}

8 0
2 years ago
Evaluate 2.43+51.62+124.77
Damm [24]
2.43 + 1.62 + 124.77 = 178.82 Because all you have to do is add up all the numbers (Don't take the decimals out, leave them in) And then you get: 178.82.

Hope I helped!

- Amber
3 0
2 years ago
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