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Mazyrski [523]
2 years ago
14

Evaluate the function

Mathematics
1 answer:
MissTica2 years ago
6 0

Answer:

-16

Step-by-step explanation:

x = -3 is less than -2, so you should use the first equation 5x-1

thus, 5(-3)-1 = -16

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Assoli18 [71]
39 miles. If d=rt and the rate is 16 mph and the time is 3 hours then 16 times 3 gives the distance of 39 miles. I could be wrong but that is what I would have done. I’m not sure if there are answer choices or not
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3 years ago
A picture frame can hold a photograph that is 16 inches long and 12 inches wide.
Lorico [155]
12 x 16 = 192 square inches
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2 years ago
Is 1/4 to the 0 power bigger then 1
marishachu [46]

Answer:

yes it is

Step-by-step explanation:

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4 0
2 years ago
Read 2 more answers
arius flipped a coin 500 times and it landed heads up 300 times. What is the relative frequency of the coin landing heads up bas
guajiro [1.7K]

Answer:

3/5

Step-by-step explanation:

500 time number of coin flipped =500

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3 0
3 years ago
Health insurers are beginning to offer telemedicine services online that replace the common office visit. A company provides a v
Veronika [31]

Answer:

\text {CI} = (60.54, \: 81.46)\\\\

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

Step-by-step explanation:

Let us find out the mean savings for a televisit to the doctor from the given data.

Using Excel,

=AVERAGE(number1, number2,....)

The mean is found to be

\bar{x} = \$71  

Let us find out the standard deviation of savings for a televisit to the doctor from the given data.

Using Excel,

=STDEV(number1, number2,....)

The standard deviation is found to be

 s = \$ 22.35

The confidence interval is given by

\text {confidence interval} = \bar{x} \pm MoE\\\\

Where the margin of error is given by

$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\

Where n is the sample of 20 online doctor visits, s is the sample standard deviation and t_{\alpha/2} is the t-score corresponding to a 95% confidence level.

The t-score is given by is

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

Degree of freedom = n - 1 = 20 - 1 = 19

From the t-table at α = 0.025 and DoF = 19

t-score = 2.093

So, the margin of error is

MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\MoE = 2.093\cdot \frac{22.35}{\sqrt{20} } \\\\MoE = 2.093\cdot 4.997\\\\MoE = 10.46\\\\

So the required 95% confidence interval is

\text {CI} = \bar{x} \pm MoE\\\\\text {CI} = 71 \pm 10.46\\\\\text {CI} = 71 - 10.46, \: 71 + 10.46\\\\\text {CI} = (60.54, \: 81.46)\\\\

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

7 0
2 years ago
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