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Mazyrski [523]
3 years ago
14

Evaluate the function

Mathematics
1 answer:
MissTica3 years ago
6 0

Answer:

-16

Step-by-step explanation:

x = -3 is less than -2, so you should use the first equation 5x-1

thus, 5(-3)-1 = -16

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Find each product.<br><br> 1. (5a3b)(2ab)<br><br> 2.5y(-y2+7y-2)<br><br> PLEASE HELP!!?!
maks197457 [2]

Answer:

<h2>1).</h2>

(5a3b)(2ab)

Expand

That's

15ab( 2ab )

we have the answer as

<h3>30a²b²</h3>

<h2>2).</h2>

5y(-y² + 7y - 2)

Expand

That's

<h3>- 5y³ + 35y² - 10y</h3>

Hope this helps you

5 0
3 years ago
What is the solution to the following system?<br> -4y=8 <br> x+3y-3z=-26<br> 2x-5y+z=19
Viktor [21]
⓵
-4ỿ = 8

Simplify the left side in order to isolate the ỿ!

-4ỿ = 8
+4 +4

Ỿ = 12

⓶
× + 3y - 3z = -26

Simplify the left side in order to isolate the ×, ỿ and z!

× + 3y - 3z = -26
÷3 ÷3

× + ỿ - 3z = -8,66 periodic
÷-3 ÷-3

× + ỿ + z = 2,88 periodic

⓷
2× - 5ỿ + z = 19

Simplify the left side in order to isolate the ×, ỿ and z!

2× - 5ỿ + z = 19
÷2 ÷2

× - 5ỿ + z = 9,5
÷-5 ÷-5

× + ỿ + z = -1,9
3 0
3 years ago
Read 2 more answers
The amount that households pay service providers for access to the Internet varies quite a bit, but the mean monthly fee is $50
Natali5045456 [20]

Answer:

(a) See Explanation

(b) \bar x =50 and \sigma_x = 0.8944

(c) The shape is normal

(d) P(\bar x > 55) = 0

Step-by-step explanation:

Given

\mu = \$50 -- mean

\sigma = \$20 --- standard deviation

n=500 --- sample size

Solving (a): The reason we can't determine the probability that an amount to access internet by a household will exceed $55.

The question says that a lot of households pay low rates, but the percentage of the households in this category is not given. This means that it is impossible to determine the shape of the distribution.

Hence, the probability cannot be calculated.

Solving (b): Sample mean and Sample standard deviation

The sample mean estimates the population mean

So:

\bar x =\mu

\bar x =50

The sample standard deviation is calculated as thus:

\sigma_x = \frac{\sigma}{\sqrt n}

\sigma_x = \frac{20}{\sqrt{500}}

\sigma_x = \frac{20}{22.36}

\sigma_x = 0.8944

Solving (c): The shape of the distribution.

We have:

n = 500 --- The sample size

According to Central limit theorem, When the sample size is greater than 30, then the shape of the distribution is normal.

<em>Hence, the shape is normal</em>

Solving (d): P(\bar x \ge 55)

Calculate the test statistic (t)

t = \frac{\bar x - \mu}{\sigma}

t = \frac{55 - 50}{0.8945}

t = \frac{5}{0.8945}

t = 5.590

So:

P(\bar x > 55) = P(t > 5.590)

Referencing the z table, we have:

P(t > 5.590) = 0

Hence:

P(\bar x > 55) = 0

5 0
3 years ago
Find the value of each variable, pls help, ty
olga nikolaevna [1]
Hope this helps


X = 8
Y = 7
6 0
3 years ago
Given the function y=x^2-3/x^2+5x+6 choose th correct horizontal asymptote.
gladu [14]
I’m almost positive it’s the second one but check to be sure
7 0
3 years ago
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