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Aloiza [94]
3 years ago
13

steve desposite $1800 per month in his saving bank account. If thi is 20% of the monthly income, find his monthly income​

Mathematics
1 answer:
Vikki [24]3 years ago
8 0

Step-by-step explanation:

Hey there!

The amount deposited= $1800

And it's just 20% of total monthly amount.

Let total amount be "x".

Then;

$1800 = 20% of X

1800 =  \frac{20}{100}  \times x

or, 180000= 20x

or, X = 180000=/20

Therefore, total monthly amount or income was $9000.

<u>Hope </u><u>it </u><u>helps!</u>

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The y-intercept will be (0,51)

In case, if you want the x-intercept it will be (-51/4,0)

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3 years ago
PLEASE HELP
Maurinko [17]
I believe this is the right way to write the function

N = [log A − log P] / log(1.0175)

N =[ log (1210.26) - log (1000)]/log (1.0175)

N =log [1210.26/1000] / log (1.0175) = log (1.21026)/log(1.0175) = 0.08288/0.00753 = 11

N = 11 months



4 0
3 years ago
Help me find three different ratios that are equivalent to 3:11!! I need a explanation too!
SVEN [57.7K]
You can do
3 * 2 and 11 * 2 which would be 6:22 and is still equal to the ratio 3:11. Your explanation can be the when divided by 2 or the number you multiplied by, you would get the original ratio
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2 years ago
Jason tracked the days of the week for the last 50 times he was assigned homework.
vovangra [49]

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3 0
3 years ago
When a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a ra
Sergeu [11.5K]

Answer:

r=\sqrt{10}\text{ m}

Step-by-step explanation:

We have been given that when a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a rate of 0.7 meters per hour. We are asked to find the approximate radius of tank in meters.

We will use volume of cylinder formula to solve our given problem as:

V=\pi r^2h, where,

r = Radius,

h = Height of cylinder.

Since the level of water in the tank rises at a rate of 0.7 meters per hour, so height of cylinder would be h = 0.7 meters at V=22\text{ m}^3.

Upon substituting these values in above formula, we will get:

22\text{ m}^3=\frac{22}{7}\cdot r^2(0.7\text{ m})

22\text{ m}^3=\frac{22}{10}\cdot r^2\text{ m}

\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}=r^2

r^2=\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}

r^2=10\text{ m}^2

Now, we will take positive square root of both sides as radius cannot be negative.

\sqrt{r^2}=\sqrt{10\text{ m}^2}

r=\sqrt{10}\text{ m}

Therefore, radius of tank would be approximately square root of 10 m.

5 0
3 years ago
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