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almond37 [142]
3 years ago
14

Im not sure how to solve this

Mathematics
1 answer:
Irina-Kira [14]3 years ago
8 0
A question:
(5.3 x 10 to the 6th power) + 8.2  10 to the 6th power)
A solution:
Multiply 10 x 10 6 times to get rid of the two powers.
(5.3 x 1,000,000) + (8.2 x 1,000,000)
Multiply inside the parenthises.
 (5,300,000) + (8,200,000)
Add:
13,500,000.
A answer:
13, 500,000.

B question:
(6.5 x 10 to the 7th power) / (5 x 10 to the 3rd power)
B solution:
Again, get rid of the powers.
(6.5 x 10,000,000) / (5 x 1,000)
Multiply inside the parenthesis:
(65,000,000) / (5,000)
Divide:
13,000
B answer:
13,000.

C question:
(4.6 x 10 to the 6th power) (3 x 10 to the 5th power) / (2 x 10 to the 7th power)
C solution:
Get rid of powers:
(4.6 x 1,000,000) (3 x 100,000) / (2 x 10,000,000)
Multiply:
(4,600,000) (300,000) / (20,000,000)
multiply in the left side:
(1,380,000,000,000) / (20,000,000)
divide:
69,000
C answer:
69,000

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Can you please check if this is correct?
Reika [66]

Answer: not sure how helpful this is, but the second one is correct (if it's the one that's corresponding to the blue line). The pink line, however, is incorrect if it is corresponding to the first equation. The first equation must have a y-intercept of 1.

Step-by-step explanation:

4 0
2 years ago
A 4-lb. force acting in the direction of (vector) 4,-2 moves an object just over 7ft from point (0,4) to (5,-1). Find the work d
Tcecarenko [31]

To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.

The work done on moving the object is 27ft*lbs

<h3>Work done in moving the object from point A to point B</h3>

To find the work done on this object, let's find the net force on the object.

Data;

  • force = 4lb
  • direction = 4, -2
  • displacement = 7ft
  • direction = (0, 4) to (5,1)

The unit vector of the force is

\sqrt{4^2 +(-2)^2} =\sqrt{16 + 4} = \sqrt{20}

\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} }

The net force acting on the object is

F = 4(\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} })\\F= (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } )

The displacement on the object is 7ft through (0,4) to (5, -1)

The unit vector on displacement is

\sqrt{5^2 + (-1-4)^2} = \sqrt{25+25} = \sqrt{50}

\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }

The net displacement will be

7(\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }) = \frac{35}{\sqrt{50} }, \frac{-35}{50}

The work done will be F.d

w = f. d \\

w = (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } ) * \frac{35}{\sqrt{50} }, \frac{-35}{50}\\w = 17.71+ 8.854\\w = 26.567 = 27ft*lbs

The work done on moving the object is 27ft*lbs

Learn more on work done on an object here;

brainly.com/question/26152883

#SPJ1

6 0
2 years ago
Triangle JKL and Triangle MNO are similar triangles.
STALIN [3.7K]
We need to work out first the scale factor of the side length

Side MN correspond to the side JK

Side MN = 3.5 cm
Side JK = 14 cm

Scale factor = 14/3.5 = 4

Side OM correspond to side LJ
Side OM = 12 cm
Side LJ = 12 × 4 = 48 cm
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Find the common ratio<br> -8,-13,-18,-23<br>A. -21<br>B. 5<br>C.-5<br>D.-23
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13. McKenzie gets a base pay of $1,800 per month. She also earns 12%
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Answer:

The answer is 7,200...........

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