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ira [324]
2 years ago
13

Definition of my computer​

Computers and Technology
2 answers:
RideAnS [48]2 years ago
8 0

Answer:

a programmable electronic device designed to accept data

Explanation:

a programmable electronic device designed to accept data

solniwko [45]2 years ago
8 0
A programmable divce
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HELP ME PLZZ FFFAAASSSTTTT
Dahasolnce [82]
The answer has to be A because we you get your licensed suspended you are un able to drive for a while Intel you take the test again and or pay a fine
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PLLZZZZZ HELP I WILL GIVE BRAINLIEST IF ANSWER IS RIGHT
Aloiza [94]

Answer:

The answer is candyCost = int(input("How much is the candy?"))

Explanation:

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Programming challenge description: Given a string comprising just of the characters (,),{,},[,] determine if it is well-formed o
nadezda [96]

Answer:

Employing Java language,

Explanation:

//for using stack data structure

import java.util.Stack;

//class definition

public class BracketMatch {

   //function to find the string is well formed or not

   public static boolean isWellFormed(String str) {

       //variable to store the character value

       char ch;

       //check if the first character itself is the end of the brackets

       if (str.charAt(0) == ')'||str.charAt(0) =='}'||str.charAt(0) ==']')

           return false;

       //creating a stack of character type

       Stack<Character> stack = new Stack<Character>();

       //iterating through the characters in string

       for(int i=0; i < str.length(); i++) {

           //storing the current character from the string in the variable

           ch = str.charAt(i);

           if(ch == '('||ch=='{'||ch=='[')

               //if the character is starting of the brackets push it into stack

               stack.push(ch);

           else if(ch == ')')

               //if it is closing bracket and the stack is empty then the string is not well formatted

               if(stack.empty())

                   return false;

               else if(stack.peek() == '(')

                   stack.pop();

               else

                   return false;

           else if(ch == '}')

               if(stack.empty())

                   return false;

               else if(stack.peek() == '{')

                   stack.pop();

               else

                   return false;

       }

       //returning the stack content, if the string will be well formed the stack would be empty

       //after all the operations

       return stack.empty();

   }

   //main method

   public static void main(String[] args) {

       //calling function to find if the string is welll formatted or not

       System.out.println(isWellFormed("{}"));

       //calling function to find if the string is welll formatted or not

       System.out.println(isWellFormed("([)]"));

   }

}

5 0
3 years ago
i have a bag of trail mix . one half of the bag is peanuts. 1/4 of the bag is chocolate candies , and 1/4 of the bag is died fru
Lelu [443]
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The likelihood of drawing a chocolate therefore is 1/4. 

The likelihood of drawing a peanut is 1/2 and the likelihood of drawing a dried fruit is 1/4.

Thus, D is the correct answer because the 1/4 likelihood of drawing a chocolate is less than the 1/2 chance of drawing a peanut.
8 0
3 years ago
Identify the equation that translates Y = In(x) five units down.​
Tatiana [17]
Y=In(x)-5
hopefully it’s right :)
4 0
2 years ago
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