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Savatey [412]
3 years ago
13

,ll hmvcvmhbbb b cbc bc bc b cb cbcb c

Computers and Technology
1 answer:
STALIN [3.7K]3 years ago
7 0

The answer is C due to the fact that u have no options and ur cool for giving me freee pints, take care

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Your _______ can help block inappropriate content online.<br> 1. web browser<br> 2. Password
djverab [1.8K]

Answer:

web browser.

Explanation:

yea let me go post my password to block content (sarcasm)

7 0
3 years ago
Your company leases a very fast internet connection and pays for it based on usage. You have been asked by the company president
azamat

Answer:

c. Install a proxy server

Explanation:

In computing a proxy server is implemented as a middle 'man' between the user and the internet. It will hence behave as a gateway that will seperate users from the websites that they browse. The major importance of a proxy server is enforcing security, however it can also act as a web filter allowing organizations to restrict access to certain websites. So when an organization or a school wishes to prevent access to certain sites a proxy server will be implemented, in the question scenario this web filter feature can be used to save cost associated with visiting sites not relevant to the organization's objectives

7 0
3 years ago
Business customers pay $0.006 per gallon for the first 8000 gallons. If the usage is more than 8000 gallons, the rate will be $0
trasher [3.6K]

Answer:

#include <bits/stdc++.h>

using namespace std;

int main()

{

   // variables

   char cust_t;

   int no_gallon;

   double cost=0;

   cout<<"Enter the type of customer(B for business or R for residential):";

   // read the type of customer

   cin>>cust_t;

   // if type is business

   if(cust_t=='b'||cust_t=='B')

   {

       cout<<"please enter the number of gallons:";

       // read the number of gallons

       cin>>no_gallon;

       // if number of gallons are less or equal to 8000

       if(no_gallon<=8000)

       {

           // calculate cost

           cost=no_gallon*0.006;

           cout<<"total cost is: $"<<cost<<endl;

       }

       else

       {

           // if number of gallons is greater than 8000

           // calculate cost

           cost=(8000*0.006)+((no_gallon-8000)*0.008);

           cout<<"total cost is: $"<<cost<<endl;

           

       }

       

   }

   

   // if customer type is residential

   else if(cust_t=='r'||cust_t=='R')

        {

           

       cout<<"please enter the number of gallons:";

       // read the number of gallons

       cin>>no_gallon;

       // if number of gallons are less or equal to 8000

       if(no_gallon<=8000)

       {

           // calculate cost

           cost=no_gallon*0.007;

           cout<<"total cost is: $"<<cost<<endl;

       }

       else

       {// if number of gallons is greater than 8000

       // calculate cost

           cost=(8000*0.005)+((no_gallon-8000)*0.007);

           cout<<"total cost is: $"<<cost<<endl;      

       }        

   }

return 0;

}

Explanation:

Ask user to enter the type of customer and assign it to variable "cust_t". If the customer type is business then read the number of gallons from user and assign it to variable "no_gallon". Then calculate cost of gallons, if  gallons are less or equal to 800 then multiply it with 0.006.And if gallons are greater than 8000, cost for  first 8000 will be multiply by 0.006 and  for rest gallons multiply with 0.008.Similarly if customer type is residential then for first 8000 gallons cost will be multiply by 0.005 and for rest it will  multiply by 0.007. Then print the cost.

Output:

Enter the type of customer(B for business or R for residential):b                                                                                            

please enter the number of gallons:9000                                                                                                                      

total cost is: $56  

4 0
4 years ago
Find the number of ideal integers within the given segment [low,high] inclusive. An ideal number is a positive integer that has
Alex Ar [27]

Answer:

  1. low = 10
  2. high = 50
  3. count = 0
  4. for i in range(low, high + 1):
  5.    if(i % 3 == 0 and i % 5 == 0):
  6.        count += 1
  7. print(count)

Explanation:

The solution code is written in Python.

We can create low and high variables to store the lower bound and upper bound in the range (Line 1-2)

Next create a counter variable, count (Line 3).

Use a for loop to traverse through the number between lower bound and upper bound and check if the current number-i is divisible by 3 and by 5, increment the count by one.

After the loop, print the count and we can get the number of ideal integers within the range (Line 8).

6 0
3 years ago
This zyLab activity prepares a student for a full programming assignment. Warm up exercises are typically simpler and worth fewe
Gwar [14]

Answer:

Following are the code to the given points:

#include <iostream>//header file

using namespace std;

int main()//defining main method

{

   cout<<"Hello World!"<<endl;//print message for code 1

   cout<<"Hello world!\nHow are you?"<<endl;//print message for code 2

   cout<<"Hello world!\nHow are you? \n \t (I'm fine).";//print message for code 3

   return 0;

}

Output:

Please find the attached file.

Explanation:

In the given code, inside the main method, three print statement is used, that prints the given message which is defined in the question, for the printing of the message we use "\n, endl, and \t".

In which the "\n and endl" both are used in C++, to break the line into a new-line, and "\t" is used for providing a tab space.

4 0
3 years ago
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