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stira [4]
3 years ago
14

Which planet experiences tidal effects that are caused by the Sun?

Physics
1 answer:
Vilka [71]3 years ago
8 0

Technically, ALL of the planets do.

The effect is greatest inside Mercury, because Mercury is the one closest to the Sun.

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A 4kg block slides freely across a rough surface such that the block slows down with an acceleration of −1.25 m/s2 . What is the
Sophie [7]

Answer:

The coefficient of kinetic friction between the block and the surface is 0.127.

Explanation:

Given that,

The mass of a block, m = 4 kg

The acceleration of the block, a = -1.25 m/s²

We need to find the coefficient of kinetic friction between the block and the surface. The force of friction is given by :

F=\mu mg\\\\ma=\mu mg\\\\\mu=\dfrac{a}{g}\\\\\mu=\dfrac{1.25}{9.8}\\\\\mu=0.127

So, the coefficient of kinetic friction between the block and the surface is 0.127.

6 0
3 years ago
You might say that this experiment was an attempt to build a scale, and then calibrate it against a scale that we trust (the ele
Allushta [10]

No.

Since repeated measurements are taken and the average and 95% confidence interval are calculated, the possibility of the lack of agreement being a random error has been minimized or even eliminated.

<h3>What is a random error?</h3>

Random error is defined as the deviation of the total error from its mean value due to chance.

Random errors can result from the instrument not being precise or from mistakes by the researcher.

Random errors can be minimized by taking multiple readings and averaging the results.

Since repeated measurements are taken and the average and 95% confidence interval are calculated, the possibility of the lack of agreement being a ransom error has been minimized.

Learn more about random errors at: brainly.com/question/22041172

3 0
3 years ago
Read 2 more answers
two identical small charged spheres are a certain distance apart, and each one initially experiences an electrostatic force of m
alexdok [17]
The electrostatic force is directly proportional to the product of the charges, by Coulomb's law.

F α Qq

If the charges are now half the initial charges: 

<span>F α (1/2)Q *(1/2)q
</span>
F α (1/4)Q<span>q

The new force when the charges are each halved is (1/4) the first initial force experienced at full charge.</span>
4 0
3 years ago
Read 2 more answers
How much work does and elephant do pulling a circus wagon 1000m with<br> an applied force of 200 N?
RideAnS [48]

Answer:

2000000 J

Explanation: Multiply 200 N by 1000 m

8 0
3 years ago
A microphone is attaced to a spring that is suspended from
kirill115 [55]

To solve this problem we will apply the concept related to the amplitude and the Doppler effect. The difference between the maximum and minimum frequency detected by the microphone would be given by the mathematical function

f_{max} - f_{min} = 2 f_s (\frac{v_0}{v})

Here,

f_s= Source Frequency

v_0 = Speed of microphone

v = Speed sound

f_{max} - f_{min} = 2 f_s (\frac{v_0}{v})

Maximum speed of the microphone is

v_0 = f_{max} - f_{min} * \frac{v}{2f_s}

v_0= \frac{2.1Hz*343m/s}{2*440Hz}

v_0= 0.8185 m/s

Now the amplitude is

A = \frac{v_0}{2\pi/T}

Here T means the Period, then

A= \frac{0.8185 * 2.0}{2\pi}

A= 0.2605m

Therefore the amplitude of the simple harmonic motion is 0.2605m

3 0
4 years ago
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