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liubo4ka [24]
3 years ago
12

Which resistors in the circuit must have the same amount of charge passing through each second?

Physics
1 answer:
Nutka1998 [239]3 years ago
5 0

Answer:

Option B) C and D

Explanation:

The amount of charge passing through a resistor each second corresponds to the definition of current, so the problem is asking "which resistors have the same amount of current".

Let's keep in mind that:

- When two resistors are in series (=they are connected into the same branch of the circuit), the current flowing through each resistor is the same

- When two resistors are in parallel (=they are connected into different branches), the potential difference across each resistor is the same

Looking at the previous definitions, we have to find the two resistors in the circuit that are connected in series. We see that resistors C and D are in the same branch, so they are in series: therefore, the current flowing through resistor C and D is the same.

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100 POINTS FOR CORRECT ANSWER/EXPLANATION
Shalnov [3]

Answer:

6 N

Explanation:

Let's start with the small block m on top.  There are four forces:

Weight force mg pulling down, normal force N₁ pushing up, tension force T pulling right, and friction force N₁μ pushing left (opposing the direction of motion).

Now let's look at the large block M on bottom.  There are seven forces:

Normal force N₁ pushing down (opposite and equal from block m),

Friction force N₁μ pushing right (opposite and equal from block m),

Weight force Mg pulling down,

Tension force T pulling right,

Applied force F pulling left,

Normal force N₂ pushing up,

and friction force N₂μ pushing right (opposing the direction of motion).

So you've correctly identified the free body diagrams.

Now apply Newton's second law.  Sum of forces in the y direction for block m:

∑F = ma

N₁ − mg = 0

N₁ = mg

Sum of forces in the x direction:

∑F = ma

T − N₁μ = 0

T = N₁μ

T = mgμ

Sum of forces in the y direction for block M:

∑F = ma

-N₁ − Mg + N₂ = 0

N₂ = N₁ + Mg

N₂ = mg + Mg

Sum of forces in the x direction:

∑F = ma

N₁μ + T − F + N₂μ = 0

F = N₁μ + T + N₂μ

F = mgμ + mgμ + (mg + Mg)μ

F = gμ(3m + M)

Since M = 2m:

F = 5gμm

Plug in values:

F = 5 (10 m/s²) (0.400) (0.300 kg)

F = 6 N

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1. You serve a volleyball with a mass of 2.1kg. The ball leaves your
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The kinetic energy is 945 joules.

Kinetic energy is the energy that an object has as a result of motion. It is defined as the effort required to accelerate a mass-determined body from rest to the indicated velocity.

The speed of an object or particle, which is a scalar quantity, is the size of the change in its location over time or the size of the change in its position per unit of time.

The mass of the volleyball is 2.1 kg.

The speed of the ball when the ball leaves the hand is 30 m/s.

m = 2.1 kg

v = 30 m/s

The kinetic energy of an object is given as:

KE = (1/2 ) × m × v²

KE = (1 / 2) × 2.1 kg × ( 30 m/s)²

KE = (1 / 2) × 2.1 kg × 30 m/s × 30 m/s

KE = 2.1 kg × 15 m/s × 30 m/s

KE = 945 J

Learn more about kinetic energy here:

brainly.com/question/8101588

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Answer:

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Explanation:

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