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Temka [501]
3 years ago
15

A pendulum with a length of 1.00 m is released from an initial angle of 12.5°. After 1 000 s, its amplitude has been reduced by

friction to 7.50°. What is the value of b/2m?
Physics
1 answer:
Viefleur [7K]3 years ago
7 0

Answer:

A student is conducting a pendulum experiment. Which of the following pieces of safety equipment would be the most vital to conduct this test?

Explanation:nduebidndo eyn h ehj jd

jknsjk Jjkfnjkjnuifvr

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What types of collisions can result from making unsafe passes?
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<span>Unsafe passes are passes with restricted line of sight, passes with cross traffic, narrow passes which are unsafe. 
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7 0
3 years ago
The electrons involved in the formation of a chemical bond are called
tatiyna

Answer: Valence electrons

Valence electrons are those that are in the outermost or superficial layer of the atom, which means they have the highest energy compared to those of the inner layers.

Because of their position, it is easier for these electrons to interact with other atoms of their own element as well as different elements. This is done through the process of forming bonds when being attracted by other atoms.

7 0
3 years ago
A child is swinging back and forth with a constant period and amplitude. Somewhere in front of the child, a stationary horn is e
Amanda [17]

Answer:

Explanation:

  We shall apply concept of Doppler's effect of apparent frequency to this problem . Here observer is moving sometimes towards and sometimes away from the source . When observer moves towards the source , apparent frequency is more than real frequency and when the observer moves away from the source , apparent frequency is less than real frequency . The apparent frequency depends upon velocity of observer . The formula for apparent frequency when observer is going away is as follows .

f = f₀ ( V - v₀ ) / V , f is apparent , f₀ is real frequency , V is velocity of sound and v is velocity of observer .

f will be lowest when v₀ is highest .

velocity of observer is highest when he is at the equilibrium position or at middle point .

So apparent frequency is lowest when observer is at the middle point and going away from the source  while swinging to and from before the source of sound .

3 0
3 years ago
2. A 50 kg diver is standing on the edge of a 15 m high cliff. What is his potential energy?
Lera25 [3.4K]

Answer:

3675 J

Explanation:

Gravitational Potential Energy = \frac{1}{2} × mass × g × height

( g is the gravitation field strength )

Mass = 50 kg

G = 9.8 N/kg ( this is always the same )

Height = 15 m

Gravitational Potential Energy = \frac{1}{2} × 50 ×9.8 × 15

= 3675 J

3 0
3 years ago
Which scientist and atomic model are correctly matched
Novosadov [1.4K]

Answer:

Rutherford and atomic model are correctly matched.

7 0
3 years ago
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