Answer:
Runner A
Explanation:
Both B and C finished the race from 25 seconds
But A runner finished it from 20 seconds
Answer:
The moment of inertial of the wheel, ![I = 8(\frac{1}{3}M_sL^2 ) + M_rL^2](https://tex.z-dn.net/?f=I%20%3D%208%28%5Cfrac%7B1%7D%7B3%7DM_sL%5E2%20%29%20%2B%20M_rL%5E2)
Explanation:
Given;
8 spokes of uniform diameter
mass of each spoke, =
length of each spoke, = L
mass of outer ring, = ![M_r](https://tex.z-dn.net/?f=M_r)
The moment of inertial of the wheel will be calculated as;
![I = 8I_{spoke} + I_{ring}](https://tex.z-dn.net/?f=I%20%3D%208I_%7Bspoke%7D%20%2B%20I_%7Bring%7D)
where;
is the moment of inertia of each spoke
is the moment of inertia of the rim
Moment of inertia of each spoke ![=\frac{1}{3}M_sL^2](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B3%7DM_sL%5E2)
Moment of inertial of the wheel
![I = 8(\frac{1}{3}M_sL^2 ) + M_rL^2](https://tex.z-dn.net/?f=I%20%3D%208%28%5Cfrac%7B1%7D%7B3%7DM_sL%5E2%20%29%20%2B%20M_rL%5E2)
Answer:
A. Distance over which the force is applied
Explanation:
As we know that in pulley system the mass of the car is balanced by the tension in the string
so here we will have
![T = r \times F](https://tex.z-dn.net/?f=T%20%3D%20r%20%5Ctimes%20F)
so here in order to decrease the force needed to lift the car we have to increase Distance over which the force is applied
So here if we increase the distance over which force is applied then it will reduce the effort applied by us in this pulley system as the torque will be more if the distance is more.