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Flauer [41]
3 years ago
8

How does the cell membrane contribute to the ability of a cell to exists in a changing

Biology
1 answer:
kolezko [41]3 years ago
7 0

Answer:

One way that a cell maintains homeostasis is by controlling the movement of substances across the cell membrane. The lipid bilayer is selectively permeable to small, nonpolar substances. Proteins in the cell membrane include cell-surface markers, receptor proteins, enzymes, and transport proteins.

Please give me a brainliest

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Calculate the mass defect for oxygen-16 given this data. Round to the 5es001-1.jpg decimal place. mass of an oxygen-16 atom: 15.
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Answer:

Explanation:

Given parameters:

Mass of oxygen atom = 15.994914amu

Mass of a proton = 1.00728amu

Mass of a neutron = 1.00866amu

Unknown:

Mass defect = ?

From the periodic table, the number of the elementary particles in a neutral Oxygen atom is given below:

           Number of protons = 8

           Number of neutrons = 8

          Number of electrons = 8

Solution

The mass defect examines the difference between the actual mass of an atom and sum of masses of the nucleons.

The mass of an atom is concentrated in the nucleus which contains protons and neutrons. Electrons have little to no weight compared with the nucleons.

    To calculate the mass defect, we first know the mass of the nucleons first:

           1 proton has a mass of  1.00728amu

           8 protons will weigh: (8 x 1.00728)amu = 8.05824amu

For the neutrons:

          1 neutron has a mass of 1.00866amu

          8 neutrons will weigh: (8 x 1.00866)amu = 8.06928amu

Mass of the nucleons = mass of protons + mass of neutrons

                                   = 8.05824amu + 8.06928amu

                                   = 16.12752amu

The mass defect = mass of the nucleons - mass of the atom

                             = 16.12752amu - 15.994914amu

                              = 0.132606amu ≅ 0.13261amu to 5 decimal places

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Hey can anyone help me with this?
jarptica [38.1K]
Yes , i would help you but the photo isn't clear . :(
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How does a endotherm and ectotherm react to the heat?
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