Answer:
-3
Step-by-step explanation:
Answer is 120
AngNPQ=2*angNRQ=120
Following are the solution parts for the given question:
For question A:
In the given question, we calculate
of the confidence interval for the mean weight of shipped homemade candies that can be calculated as follows:

Using the t table we calculate
When
of the confidence interval:
So
confidence interval for the mean weight of shipped homemade candies is between
.
For question B:

Here we need to calculate
confidence interval for the true proportion of all college students who own a car which can be calculated as

Using the Z-table we found
therefore
the confidence interval for the genuine proportion of college students who possess a car is
So
the confidence interval for the genuine proportion of college students who possess a car is between 
For question C:
- In question A, We are
certain that the weight of supplied homemade candies is between 392.47 grams and 427.53 grams. -
In question B, We are
positive that the true percentage of college students who possess a car is between 0.28 and 0.34.
Learn more about confidence intervals:
brainly.in/question/16329412
Answer: 34%.
By definition of normal distribution, ≈68% of the data is within 1 standard deviation of the mean. Therefore 68% of IQs are between 85 and 115, and half of that is on the lower end, 85 to 100.
Answer:
(2x)X-12
Step-by-step explanation:
x-6.x-2