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enyata [817]
2 years ago
8

Which of the following ratios is equivalent to 5 to 20

Mathematics
1 answer:
morpeh [17]2 years ago
4 0
<h2><em>which of the following ratios is equivalent to 5 to 20</em></h2>

  • <em>10:40</em>

Step-by-step explanation:

<em>because 5/20=1/4 and 10/40 is also equal to 1/4.</em>

<em>hope </em><em>it</em><em> helps</em>

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PLEASE HELP
sweet [91]

Answer:

a)2 + 3 + 5 + 6 = 16

b)8a + b-9

c)8a - 28b + 15c

Step-by-step explanation:

We are given the following in the question:

1. Equivalent expression

2 + 3 + 5 + 6

Since all the terms are like terms, we can write,

2 + 3 + 5 + 6 = 16

2. Sum of given expression

(8a - 2b - 4) \text{ and } (3b - 5)\\ (8a - 2b - 4) + (3b -5)\\= 8a -2b -4 + 3b -5\\\text{Collecting the like terms}\\8a + (-2b+3b) + (-4-5)\\= 8a + b-9

3. Standard form of the expression

4(2a) + 7(-4b) + (3 \times c \times 5)\\=(8a) + (-28b) + (15c)\\=8a - 28b + 15c

which is the required standard form of the given expression.

8 0
3 years ago
7 pipes fill a tank in 50 minutes. How many minutes does it take if there are 11 pipes?
Alekssandra [29.7K]

Answer: With 11 pipes, you need 31.82 minutes to fill the tank.

Step-by-step explanation:

Let's define R as the rate at which one single pipe can fill a tank.

We know that 7 of them can fill a tank in 50 minutes, then we have the equation:

7*R*50min = 1 tank

Whit this equation, we can find the value of R:

R = 1 tank/(7*50min) = (1/350) tank/min.

Now that we know the value of R, we can do the same calculation but now with 11 pipes.

Then the time needed to fill the tank, T, is such that:

11*(1/350 tank/min)*T = 1 tank

We need to isolate T.

T = 1 tank/(11*(1/350 tank/min)) = 31.82 min

With 11 pipes, you need 31.82 minutes to fill the tank.

5 0
3 years ago
What is the vertex of the function in #5
ziro4ka [17]
Where is the function
5 0
3 years ago
Which model represents the product 3/4 x 1/3
dlinn [17]

Answer:

The first one

Step-by-step explanation:

5 0
3 years ago
Un escalador sube 225m de altura. El asenso lo hizo en 3 etapas. En la primera subio un quinto en la, en la tercera un cuarto. ¿
kiruha [24]

Answer:

Segunda etapa= 123.75 metros

Step-by-step explanation:

Altura total= 225 metros

<u>En la primera estapa subió el 20% (un quinto):</u>

Primera etapa= 225*0.2= 45 metros

<u>En la tercera etapa subió 25% (un cuarto):</u>

Tercera etapa= 225*0.250 56.25 metros

Ahora debemos determinar cuánto subió en la segunda etapa:

Segunda etapa= altura total - total subido

Segunda etapa= 225 - (45 + 56.25)

Segunda etapa= 123.75 metros

6 0
3 years ago
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