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3 years ago

9

Solve 3q - 5 = 13 for q. q =

2 answers:

Anarel [89]3 years ago

4 0

Answer:

q= 12

Step-by-step explanation:

inn [45]3 years ago

3 0

Answer:

q = 6 :))))))))))))))))))))))))

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Jenna's class brought in 40 pieces of fruit for a celebration and 12 pieces of fruit were eaten. What percentage of the fruit wa

aleksklad [387]

Answer:

70 percent of the fruit has not been eaten.

Step-by-step explanation:

Hope this helps ^^✨

3 0

3 years ago

Simplify 7N - 2N + 3P +2P

MissTica

7n-2n+3p+2p
5n+5p (combine like terms)

the answer is 5n+5p

3 0

3 years ago

Read 2 more answers

Gina wants to go to the water park with her friends. They have a total of w dollars to buy 5 tickets. Each ticket costs 15 dolla

irinina [24]

Answer:

Step-by-step explanation:

I think 75 dollars

4 0

3 years ago

Find the indicated nth partial sum of the arithmetic sequence.<br> −7, −3, 1, 5, . . ., n = 30

TiliK225 [7]

Step-by-step explanation:

Given the Arithmetic sequence

$-7, -3, 1, 5, . . .$

An arithmetic sequence has a constant difference d and is defined by

$a_n=a_1+\left(n-1\right)d$

$\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n$

$-3-\left(-7\right)=4,\:\quad \:1-\left(-3\right)=4$

$\mathrm{The\:difference\:between\:all\:of\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}$

$d=4$

$\mathrm{The\:first\:element\:of\:the\:sequence\:is}$

$a_1=-7$

as

$a_n=a_1+\left(n-1\right)d$

$\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:$

$a_n=4\left(n-1\right)-7$ ∵ $d=4$

$\mathrm{Arithmetic\:sequence\:sum\:formula:}$

$n\left(a_1+\frac{d\left(n-1\right)}{2}\right)$

$\mathrm{Plug\:in\:the\:values:}$

$n=30,\:\space a_1=-7,\:\spaced=4$

$=30\left(-7+\frac{4\left(30-1\right)}{2}\right)$

$=30\left(58-7\right)$ ∵ $\frac{4\left(30-1\right)}{2}=58$

$=30\cdot \:51$

$=1530$ ∵ $\mathrm{Multiply\:the\:numbers:}\:30\cdot \:51=1530$

Therefore, the indicated nth partial sum of the arithmetic sequence is 1530.

ANOTHER METHOD

as

$a_n=4\left(n-1\right)-7$

n = 30

$\sum _{n=1}^{30}\:4\left(n-1\right)-7$

$=\sum _{n=1}^{30}4n-11$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \sum a_n+b_n=\sum a_n+\sum b_n$

$=\sum _{n=1}^{30}4n-\sum _{n=1}^{30}11$

as

$\sum _{n=1}^{30}4n=1860$

and

$\sum _{n=1}^{30}11=330$

so

$=1860-330$

$=1530$

7 0

4 years ago

Nora is three times the age of Cora. In 5 years time, the sum of their ages will be 38. How old are they?

kiruha [24]

Step-by-step explanation:

x+5=3(x-3)

X+5= 3x-3

x-3x=-3-5

-2x=-8

X= -8/-2

X=4 Answer

4 0

3 years ago