Answer: 6.5<6.55
Step-by-step explanation: Because you add the zero to the 6.50 but it’s still less than 6.55.
Answer:
The probability is 
Step-by-step explanation:
We can divide the amount of favourable cases by the total amount of cases.
The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8,
For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function
with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.
Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.
We can conclude that the probability for 8 rooks not being able to capture themselves is

Answer:
The equation of the line is 6y = 7x + 23
Step-by-step explanation:
We begin by calculating the slope of the line;
mathematically, the slope is given by;
m = (y2-y1)/(x2-x1)
That would be;
m= (5-(-2))/(1-(-5))
m = 7/6
So the equation becomes;
y = 7/6x + b
We below need to get the value of the y-intercept b
We get this by making a substitution for any of the two points
Let’s say we make the substitution for (-5,-2) in which case y = -2 and x = -5
Thus, we have
-2 = 7/6(-5) + b
-2 = -35/6 + b
b = -2 + 35/6
b = (-12+ 35)/6 = 23/6
So we have;
y = 7/6x + 23/6
let’s multiply through by 6
6y = 7x + 23
First use distributive property. Then isolate the variable and get x=2.