The given functions are

Evaluate the functions.
1. Because 7/4 > 1 and the exponent is positive,
the function does not decay.
2.Because 4/5 < 1 and the exponent is negative,
the function does not decay.
3. Because 8/7 > 1 and the exponent is negative,
the function decays.
4. Because 9/2 > 1 and the exponent is positive,
the function does not decay.
A composite plot the functions verifies the answer.
Answer:
Answer: 6.46 is your answer
Step-by-step explanation:
Answer:
Proved
Step-by-step explanation:
To prove that every point in the open interval (0,1) is an interior point of S
This we can prove by contradiction method.
Let, if possible c be a point in the interval which is not an interior point.
Then c has a neighbourhood which contains atleast one point not in (0,1)
Let d be the point which is in neighbourhood of c but not in S(0,1)
Then the points between c and d would be either in (0,1) or not in (0,1)
If out of all points say d1,d2..... we find that dn is a point which is in (0,1) and dn+1 is not in (0,1) however large n is.
Then we find that dn is a boundary point of S
But since S is an open interval there is no boundary point hence we get a contradiction. Our assumption was wrong.
Every point of S=(0, 1) is an interior point of S.
Answer:
0.527
Step-by-step explanation:
From the question,
The sequence is Geometry Progression (G.P)
Tₙ = arⁿ⁻¹.......................... Equation 1
Where n = number of term, a = first term, r = common ratio
Given: n = 7, a = 6, r = 2/3
Substitute these values into equation 1
T₇ = 6(2/3)⁷⁻¹
T₇ = 6(2/3)⁶
T₇ = 6(64/729)
T₇ = 384/729
T₇ = 0.527
Hence, the 7th term of the sequence is 0.527