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2 years ago

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Mathematics

2 answers:

adelina 88 [10]2 years ago

8 0

Answer:

ssxq

Step-by-step explanation:

andrew-mc [135]2 years ago

8 0

Answer:

Hello. How's your day been so far?

Step-by-step explanation:

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NEED ANSWER ASAP!!! PLEASE HELP

lys-0071 [83]

Answer:

Answer "C"

Step-by-step explanation:

I believe this because it would not make sense to compare the already known equation to the unknown equation and does make sense to compare the unknown equation to the known equation

(pls dont delete this moderators)

3 0

2 years ago

What is the answer for(y⁴)³

Natasha2012 [34]

The answer to the problem is y^12

8 0

2 years ago

Read 2 more answers

Find the volume of the solid.

dmitriy555 [2]

In Cartesian coordinates, the region (call it $R$ ) is the set

$R = \left\{(x,y,z) ~:~ x\ge0 \text{ and } y\ge0 \text{ and } 2 \le z \le 4-x^2-y^2\right\}$

In the plane $z=2$ , we have

$2 = 4 - x^2 - y^2 \implies x^2 + y^2 = 2 = \left(\sqrt2\right)^2$

which is a circle with radius $\sqrt2$ . Then we can better describe the solid by

$R = \left\{(x,y,z) ~:~ 0 \le x \le \sqrt2 \text{ and } 0 \le y \le \sqrt{2 - x^2} \text{ and } 2 \le z \le 4 - x^2 - y^2 \right\}$

so that the volume is

$\displaystyle \iiint_R dV = \int_0^{\sqrt2} \int_0^{\sqrt{2-x^2}} \int_2^{4-x^2-y^2} dz \, dy \, dx$

While doable, it's easier to compute the volume in cylindrical coordinates.

$\begin{cases} x = r \cos(\theta) \\ y = r\sin(\theta) \\ z = \zeta \end{cases} \implies \begin{cases}x^2 + y^2 = r^2 \\ dV = r\,dr\,d\theta\,d\zeta\end{cases}$

Then we can describe $R$ in cylindrical coordinates by

$R = \left\{(r,\theta,\zeta) ~:~ 0 \le r \le \sqrt2 \text{ and } 0 \le \theta \le\dfrac\pi2 \text{ and } 2 \le \zeta \le 4 - r^2\right\}$

so that the volume is

$\displaystyle \iiint_R dV = \int_0^{\pi/2} \int_0^{\sqrt2} \int_2^{4-r^2} r \, d\zeta \, dr \, d\theta \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} \int_2^{4-r^2} r \, d\zeta\,dr \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} r((4 - r^2) - 2) \, dr \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} (2r-r^3) \, dr \\\\ ~~~~~~~~ = \frac\pi2 \left(\left(\sqrt2\right)^2 - \frac{\left(\sqrt2\right)^4}4\right) = \boxed{\frac\pi2}$

3 0

10 months ago

What is the mean of 17, 9, 11,7/

Anna11 [10]

Answer:

Step-by-step explanation:

17 + 9 +11 + 7 = 44

44/4 = 11

3 0

1 year ago

I just need the equations for numbers 5 and 7 ask soon as possible thanks

docker41 [41]

I’m sorry I don’t know

4 0

2 years ago