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3 years ago

Determine if this is a function.

Mathematics

1 answer:

Kruka [31]3 years ago

6 0

Answer: This is not a function

Why not?

The input x = 2 leads to more than one output. In this case, it leads to y = 20 and y = 40 simultaneously. This is the reason why we don't have a function. A function is only possible if each input x leads to exactly one y output.

Put another way: we cannot have x repeating any values if we want a function.

Side note: We could have y repeat however. So it's possible to have a function with the two points (1,5) and (3,5).

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Find the circumference of the circle shown below if the diameter equals 20 inches. Use 3.14 for π.

Rasek [7]

Answer:

62.83

because you take 20, divide it by 2 to get the radius then you have the equation 2π(10)

3 0

4 years ago

A school wants to build a rectangular playground that will have a diagonal length of 75 yards. How wide can the playground be if

Naddika [18.5K]

A rectangle has two diagonals. Each one is a line segment drawn between the opposite vertices (corners) of the rectangle. By using the Pythagorean Theorem, we can calculate the width. We do as follows:

c^2 = a^2 + b^2
a = sqrt( c^2 - b^2 )
a = 68.74 yards

5 0

3 years ago

Please help I don’t understand this

maks197457 [2]

Answer:

1. Swim practice $\leq$ 35 laps

2. ran<5 miles

3. occupancy<437 people

im sorry i cant draw something else out for the other questions

Step-by-step explanation:

6 0

3 years ago

lled a 12:3:112:3:1 ratio. Such a model can provide the basis for the null hypothesis in a significance test. A cross of white a

nadezda [96]

Here is the full question:

When a species has several variants of a phenotype passed on from generation to generation, we can form a hypothesis about the genetics of the trait based on Mendelian theories of genetic inheritance. For example, in a two-gene dominant epistatic model, the first gene masks the effect of the second gene, leading to the expression of three phenotype variants. Crossing the dominant and recessive homozygote lines would result in a second generation represented by a mix of dominant, intermediate, and recessive phenotype variants in the expected proportions: and respectively, also called a 12:3: 1 ratio.

Such a model can provide the basis for the null hypothesis in a significance test. A cross of white and green summer squash plants gives the number of squash in the second generation F2: 131 white squash, 34 yellow squash, and 10 green squash. Are these data consistent with a 12: 3: 1 dominant epistatic model of genetic inheritance( white being dominant)?

The null hypothesis for the chi-square goodness-of-fit test is

Answer:

The null hypothesis for the chi-square goodness-of-fit test is :

$\mathbf{H_o:p_{white} = \frac{12}{16}, p_{yellow} = \frac{3}{16}; p_{green} = \frac{1}{16} }$

Step-by-step explanation:

The objective of this question is to state the null hypothesis for the chi-square goodness-of-fit test.

Given that:

There are three colors associated with this model . i,e White , yellow and green and they are in the ratio of 12:3:1

The total number of these color traits associated with this model = 12 + 3 + 1 = 16

Thus ;

The null hypothesis for the chi-square goodness-of-fit test is :

$\mathbf{H_o:p_{white} = \frac{12}{16}, p_{yellow} = \frac{3}{16}; p_{green} = \frac{1}{16} }$

3 0

3 years ago

Please help asap!!!!

Lana71 [14]

Answer:

No.

Step-by-step explanation:

If you rotate it at any angle, it will not appear like this. This picture is here to fool you. This is the one angle that it looks perfectly simmetrical.

Thus, the answer is no.

4 0

3 years ago