Answer:
<em>angle ABD =</em><u><em>55 degree</em></u>
<em>angle BCD= </em><u><em>125 degree</em></u>
Step-by-step explanation:
angle ABD and angle DBC are supplementary angles.
Hence, angle ABD +angle DBC = 180 --equation 1
angle ABD = (2x+15) ---equation 2
angle BCD = (4x+45) ------equation 3
ABD+DBC=180
(2x+15) + ( 4x+45 ) = 180
2x+4x+15+45=180
6x+60=180
6x=180-60
6x=120
x=120/6=20
angle ABD= 2x+15= 2(20) +15
=40+15= 55 degree
angle BCD= 4x+45 = 4(20) +45
= 80+45= 125 degree
Hence, angle ABD =55 degree
angle BCD= 125 degree
<em>Hope this helps.</em>
