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Margaret [11]
3 years ago
7

Help due today please ​

Mathematics
1 answer:
horsena [70]3 years ago
7 0

Answer:

<em>angle ABD =</em><u><em>55 degree</em></u>

<em>angle BCD= </em><u><em>125 degree</em></u>

Step-by-step explanation:

angle ABD and angle DBC are supplementary angles.

Hence, angle ABD +angle DBC = 180 --equation 1

angle ABD = (2x+15) ---equation 2

angle BCD = (4x+45) ------equation 3

ABD+DBC=180

(2x+15) + ( 4x+45 ) = 180

2x+4x+15+45=180

6x+60=180

6x=180-60

6x=120

x=120/6=20

angle ABD= 2x+15= 2(20) +15

                              =40+15= 55 degree

angle BCD= 4x+45 = 4(20) +45

                                = 80+45= 125 degree

Hence, angle ABD =55 degree

            angle BCD= 125 degree

<em>Hope this helps.</em>

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