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egoroff_w [7]
2 years ago
6

What is the length of the line segment with endpoints (−3, 8) and (7, 8) ?

Mathematics
2 answers:
Anuta_ua [19.1K]2 years ago
8 0

Answer:

10 units

Step-by-step explanation:

because its -3 so to become postive you add 3 then add 7 = 10

hope this helped <3

Darina [25.2K]2 years ago
4 0

Answer:

10 units

Step-by-step explanation:

hope this helps

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Nathan has a sculpture in the shape of a pyramid. The height of the sculpture is 3 centimeters less than the side length, x, of
uysha [10]
Let
x-----------> <span>the side length of a pyramid square base
h-----------> t</span>he height of the sculpture <span>in the shape of a pyramid

we know that
h=(x-3)
Volume=162 cm</span>³
Volume=x² *(x-3)/3
then
x² *(x-3)/3=162----------> x³-3x²=486----------> x³-3x²-486=0
x³-3x²-486=0-------- <span>this equation can be used to find the length of the sculpture’s base 

using a graph tool-----------> </span>to find the solution
x=9 cm -------------> see the attached figure
h=(x-3)-----> h=9-3--------> h=6 cm

the answer is
<span>the length of the sculpture’s base is 9 cm
</span>the height of the sculpture is 6 cm

8 0
3 years ago
Which of the following is not a factor of 9 ?
faltersainse [42]

Answer:

2, 4, 5, 6, 7, 8

Step-by-step explanation:

6 0
2 years ago
Solve the following system of equations using the elimination method. 4x + 2y = 12 4x + 8y = –24
Hunter-Best [27]

Answer:

my answer for y is -6, x is -10

Step-by-step explanation:

just eliminate the -4s by subtracting them and you will get the value of y.

now you can use either eqn (I) or (ii) which are first and second.

anyone you decide to choose just replace y by the value you got and you will get the value of x.

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4 0
2 years ago
A central purple circle labeled O has 2 concentric rings around it. The inner ring has 2 small green spheres. The outer ring has
natulia [17]

Answer:

Its C

Step-by-step explanation:

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8 0
2 years ago
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What number must you add to complete the square? x2 + 8x = 15
Lisa [10]
Is that x squared ?
6 0
3 years ago
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