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frez [133]
3 years ago
5

Given a sequence is defined by the explicit definition t_n= n^2+nt n = n 2 + n, find the 4th term of the sequence. (i.e. t_4t 4)

Mathematics
2 answers:
Ne4ueva [31]3 years ago
7 0

<em>*100% CORRECT ANSWERS</em>

kykrilka [37]3 years ago
5 0

Answer:

Question 1:  20

Question 2: 27

Step-by-step explanation:

Question 1:  

Given a sequence is defined by the explicit definition t_{n} = n^{2} + n

Therefore, the 4th term i.e. t_{4} = 4^{2} + 4 = 20 (Answer)

So, the third option is correct.

Question 2:  

Given a sequence is defined by the explicit definition t_{n} = 2^{n} - n

Therefore, the 5th term i.e. t_{5} = 2^{5} - 5 = 27 (Answer)

So, the third option is correct.

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I have no idea!! Please help!!!
Ber [7]
The area of a traingle is \frac{1}{2}bh
So we need to know the base and the height
To work out the sides of a right angle triangle we can use a²+b²=c
c is the hypotenuse and a and b are the other sides
Because this triangle is isoceles we know that a and b are the same

a²+b²=c²
a²+a²=c²
2a²=c²
2a²=(x√6)²
2a²=(x√6)(x√6)
2a²=x²+x√6+x√6+6
2a²=x²+x√6+x√6+6
a²=\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}
a=\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}

A=\frac{1}{2}bh
A=\frac{1}{2}a*a
A=\frac{1}{2}×\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}×\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}
A=\frac{1}{2}×\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}
A=\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{4}
8 0
3 years ago
Substract 8 times the sum of a and b from 9y​
erastovalidia [21]

Answer:

Step-by-step explanation:

according to the question ur equation is

9y-8(a+b)

9y-8a-8b

6 0
3 years ago
Read 2 more answers
PLS HELP c:
Leona [35]

Answer:

108, 108, 72

Step-by-step explanation:

Vertical angles are congruent and if the measure of 1 of the angles is 72 degrees and straight lines equal 180 degrees you have to subtract 72 from 180 which equals 108.

4 0
3 years ago
PLEASE HELP
Studentka2010 [4]
<span>The side length for a cube 
with volume 8000cm3 = 8000^(1/3)= 20 m
Cheers,
Stan H.</span>8000=S^3<span>8000=20^3
so the answer will be B</span>
3 0
4 years ago
Find area of a parallelogram with a height of 8 inches and a base of 14 inches
12345 [234]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{112 \:  {inches} \: ^{2} }}}}}

Step-by-step explanation:

Given,

Height of a parallelogram ( h ) = 8 inches

Base of a parallelogram ( b ) = 14 inches

Area of a parallelogram ( A ) = ?

<u>Finding </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>parallelogram</u>

<u>\boxed{ \sf{area \: of \: parallelogram \:  =  \: base \:  \times  \: height}}</u>

⇒<u>\sf{area \: of \: parallelogram \:  =  \: 14  \: \times 8}</u>

⇒<u>\sf{area \: of \: parallelogram = 112 \:  {inches}^{2} }</u>

Hope I helped!

Best regards! :D

4 0
4 years ago
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