In a trapezoid with bases of lengths a and b, a line parallel to the bases is drawn through the intersection point of the diagon
2 answers:
Answer:
Consider the trapezoid ABCD. In this trapezoid BC=a and AD=b.
Since triangles BOC and AOD are somilar, then
[tex] \dfrac{AO}{OC}=\dfrac{DO}{OB}=\dfrac{AD}{BC}=\dfrac{b}{a}. [\tex]
OC/AO = OB/DO = BC/AD=/ba
Triangles OAE and CAB are similar
EO/BC=b/(a+b)
EO=ab/(a+b)
again
OF=ba/(b+a)
and.
EF=2a/(a+b) is arequired length.
You might be interested in
The volume of a sphere uses the following formula:
Because the question asks to use 3.14 in place of pi, the formula will now look like this:
We are given a diameter of 118 feet. The radius is half of the diameter, so divide the diameter by 2 to find the radius:
Plug this value into the formula, and solve with a calculator:
Although our result is one cubic foot off, the answer is <span>A. 859,852ft^3.
(859,852 is the result if the constant in the given formula is 4.18666, but the result with infinitely repeating numbers is 859,853.)</span>
Because the question asks to use 3.14 in place of pi, the formula will now look like this:
We are given a diameter of 118 feet. The radius is half of the diameter, so divide the diameter by 2 to find the radius:
Plug this value into the formula, and solve with a calculator:
Although our result is one cubic foot off, the answer is <span>A. 859,852ft^3.
(859,852 is the result if the constant in the given formula is 4.18666, but the result with infinitely repeating numbers is 859,853.)</span>