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11111nata11111 [884]
3 years ago
11

-5,-7 reflected across the x-axis

Mathematics
1 answer:
MakcuM [25]3 years ago
4 0

Answer:

-5,7

Step-by-step explanation:

please make me brainiest thx

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Hello sam hhehehe .dk ;
pickupchik [31]

Answer:

hello

Step-by-step explanation:

6 0
3 years ago
See the ​attached file.
Masja [62]

f(x) = 4x - x^2

1)

f(4) = 4(4) - 4^2 = 16 - 16 = 0

f(-4) = 4(-4) - (-4)^2 = -16 - 16 = -32

f(4) - f(-4) = 0 - (-32) = 32

2)

f(3/2) = 4(3/2) - (3/2)^2

f(3/2) = 6 - 9/4 = 15/4

√f(3/2) = √(15/4) = √15 / 2

3)

f(x + h) = 4(x + h) - (x + h)^2

= 4x + 4h -(x^2 + 2xh + h^2)

= 4x + 4h -x^2 - 2xh - h^2

f(x - h) = 4(x - h) - (x - h)^2

= 4x - 4h -(x^2 - 2xh + h^2)

= 4x - 4h -x^2 + 2xh - h^2

So

[f(x + h) -f(x - h) ] / 2h

= [4x + 4h -x^2 - 2xh - h^2 - ( 4x - 4h -x^2 + 2xh - h^2 )] / 2h

=( 4x + 4h -x^2 - 2xh - h^2 - 4x + 4h + x^2 - 2xh + h^2 ) / 2h

= (8h - 4xh) / 2h

= 2h(4 -2x) / 2h

= 4 - 2x

Answer: [f(x + h) -f(x - h) ] / 2h = 4 - 2x

3 0
2 years ago
Oreos 2.98 for 15.5.Oz or chips ahoy for 2.50 for 14.Oz I pick chips ahoy BUT ITS ASKING UNIT RATE CENTS PER OZ
LiRa [457]

Answer:

Unit rate of oreos = 19.23 cents/oz

Unit rate of Chips Ahoy = 17.86 cents/oz

The cheapest and most affordable is the chips ahoy because it has a lower unit rate.

Step-by-step explanation:

Oreos 2.98 for 15.5.Oz or chips ahoy for 2.50 for 14.Oz I pick chips ahoy BUT ITS ASKING UNIT RATE CENTS PER OZ

We would be finding the Unit Rate of each product.

For Oreos

Oreos $2.98 for 15.5.Oz

We convert dollars to cents

1 dollars = 100 cents

2.98 dollars = x

x = 2.98 × 100 cents

= 298 cents

Hence, the unit rate in cents/oz

= 298 cents/15.5 oz

= 19.225806452 cents/oz

= 19.23 cents/oz

For Chips ahoy

$2.50 for 14.Oz

We convert dollars to cents

1 dollars = 100 cents

2.50 dollars = x

x = 2.50 × 100 cents

= 250 cents

Hence, the unit rate in cents/oz

= 250 cents/14 oz

= 17.857142857 cents/oz

= 17.86 cents/oz

Therefore, the cheapest and most affordable is the chips ahoy because it has a lower units rate.

8 0
3 years ago
Proportions and Similarity
nekit [7.7K]

\bf \cfrac{length}{width}\qquad \qquad \stackrel{A}{\cfrac{4}{5}}\qquad \stackrel{B}{\cfrac{20}{25}}\implies \cfrac{4}{5}\qquad \checkmark

5 0
3 years ago
How are determinants used to find areas of polygons?
ANTONII [103]
When you arrange the N points in sequence around the polygon (clockwise or counterclockwise), the area is half the magnitude of the sum of the determinants of the points taken pairwise. The N determinants will also include the one involving the last point and the first one.

For example, consider the vertices of a triangle: (1,1), (2,3), (3,-1). Its area can be computed as
  (1/2)*|(1*3-1*2) +(2*-1-3*3) +(3*1-(-1)*1)|
  = (1/2)*|1 -11 +4| = 3

4 0
3 years ago
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