Answer:
3rd box = 6
6th box = -22
y=x-12
output = input-12
Step-by-step explanation:
Step-by-step explanation:
1. 
<u>Combine Like Terms:</u>
<u>Answer:</u> 
G
2. 
<u>Combine Like Terms:</u>
<u>Answer:</u> 
B
3. 
<u>Combine Like Terms:</u>
<u>Answer:</u> 
I
4. 
<u>Combine Like Terms:</u>
<u>Answer:</u> 
H
Your code is, GBIH
Answer:
P(A∩B) = 0.522
Step-by-step explanation:
Let's call A the event that a puppy is adopted and B the probability that a puppy live 7 or more years
So, the probability P(A∩B) that a randomly selected puppy in the shelter will get adopted and live 7 or more years is:
P(A∩B) = P(A)*P(B/A)
Because A and B are not independents.
Then, the probability P(A) that a puppy is adopted is 58% and the probability P(B/A) that a puppy live 7 or more years given that the puppy is adopted is 90%.
Finally, replacing the values, we get:
P(A∩B) = 0.58*0.9 = 0.522
It means that the 52.2% of the puppies are adopted and live 7 or more years.
Answer:
Step-by-step explanation:
The catch here is to break up sqrt(6) into 2 parts that use primes to define sqrt(6)
sqrt(3)* sqrt(6)
sqrt(6) can be broken up into sqrt(2*3) which equals sqrt(2)*sqrt(3)
sqrt(3)*sqrt(2)(sqrt(3)
sqrt(3)*sqrt(3)*sqrt(2)
3*sqrt(2)
