Question

The probability that a randomly selected​ 5-year-old male horned beetle will live to be 6 years old is 0.25624.​

Answer 1

Answer:

(a) The probability that two randomly selected​ 5-year-old male horned beetles will live to be 6 years​ old is 0.06566.

(b) The probability that six randomly selected​ 5-year-old male horned beetles will live to be 6 years​ old is 0.000283.

Step-by-step explanation:

It is given that the probability that a randomly selected​ 5-year-old male horned beetle will live to be 6 years old is 0.25624.​

(a)

We need to find the probability that two randomly selected​ 5-year-old male horned beetles will live to be 6 years​ old.

$P=0.25624\times 0.25624=(0.25624)^2=0.0656589376\approx 0.06566$

Therefore the probability that two randomly selected​ 5-year-old male horned beetles will live to be 6 years​ old is 0.06566.

(b)

We need to find the probability that six randomly selected​ 5-year-old male horned beetles will live to be 6 years​ old.

$P=0.25624\times 0.25624\times 0.25624\times 0.25624\times 0.25624\times 0.25624=(0.25624)^6=0.000283061988948\approx 0.000283$

Therefore the probability that six randomly selected​ 5-year-old male horned beetles will live to be 6 years​ old is 0.000283.

Answer 2

Answer: (a)  0.0656

(b) 0.00028

Step-by-step explanation:

Since we have given that

Probability that a randomly selected 5-year old male horned beetle will live to be 6 years old = 0.25624

If there are

Number of male horned beetles = 2

So, probability that two randomly selected​ 5-year-old male horned beetles will live to be 6 years​ old is given by

$(0.25624)^2\\\\=0.0656$

If number of male horned beetles = 6

So, probability that six randomly selected​ 5-year-old male horned beetles will live to be 6 years​ old is given by

$(0.25624)^6\\\\=0.00028$

Hence, (a)  0.0656

(b) 0.00028