Write 0.824 as a fraction in the simplest form

Can u plz help me look at the photo<br><br> PLZ NO LINKS

djyliett [7]

Answer:

0.07

Step-by-step explanation:

The hundredths place is the place between the tenths and thousandths place. For example, the digit in the tenths place in 0.073 is 7.

To round to the nearest hundredth, we look to the digit right of the hundredth digit, 7. We notice that the digit in the thousandths place is 3. When rounding, if a number is 4 or less, we change that digit to a 0, along with the digits beyond it. If a number is 5 or more, we bump up the digit to the next number. Since 3 is less than 4, we change 0.073 to 0.07.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

8 0

2 years ago

Question in picture solve

dimulka [17.4K]

Answer:

x= 13.5

Step-by-step explanation:

f(x) = 2x + 9

f(x) = 36

Set the 2 equations equal to each other;

2x + 9 = 36

Subtract 9 from both sides;

2x = 27

Divide both sides by 2;

x = 13.5

<em>Check:</em>

f(x) = 2x + 9

f(13.5) = 2(13.5) + 9= 27 + 9 = 36

3 0

3 years ago

Every day, Luann walks to the bus stop and the amount of time she will have to wait for the bus is between 0 and 12 minutes, wit

Nana76 [90]

Answer:

a. 341.902.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

n instances of a normal variable:

For n instances of a normal variable, the mean is $n\mu$ and the standard deviation is $s = \sigma\sqrt{n}$