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love history [14]
3 years ago
8

Is this statement true or false? * If an odd number is less than 15, then it is prime.

Mathematics
1 answer:
Hatshy [7]3 years ago
8 0

Answer: That is false

Step-by-step explanation: 9 is odd but not prime

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A set of equations is given below:
ipn [44]
The correct answer is 'Equation F can be written as 2d + 1 = 3d + 7'. In order to find the answer to a system of equations, the two equations must be set equal to each other. For instance, if we had the equations x = y + 1 and x = 3y - 1, we would set the two equations equal to one another to find the answer.

x = y + 1
x = 3y - 1
y + 1 = 3y - 1
1 = 2y - 1
2 = 2y
1 = y

x = y + 1
x = 1 + 1
<span>x = 2

We can use this to solve the set of equations above.

</span><span>2d + 1 = 3d + 7
</span>1 = d + 7
-6 = d

c = 2d + 1
c = 2(-6) + 1
c = -12 + 1
c = -11

Hope this helps!
6 0
3 years ago
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Would the answer be A ) 15 or B ) 18?
Stels [109]
Your answer is (A 15)
6 0
3 years ago
!!Help!!<br>solve for x​
Murrr4er [49]

WXY = XYW ( = 41 ) ⇒  XYW is a isosceles triangle

⇒ XW = YW

⇒ 54 = 6x + 6

⇒ 6( x + 1 ) = 54

⇒ x + 1 = 9

⇒ x = 8

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4 0
3 years ago
Given that u =&lt; 2,12 &gt;, and z =&lt; -7,5 &gt;
swat32

Using the dot product:

For any vector x, we have

||x|| = √(x • x)

This means that

||w|| = √(w • w)

… = √((u + z) • (u + z))

… = √((u • u) + (u • z) + (z • u) + (z • z))

… = √(||u||² + 2 (u • z) + ||z||²)

We have

u = ⟨2, 12⟩   ⇒   ||u|| = √(2² + 12²) = 2√37

z = ⟨-7, 5⟩   ⇒   ||z|| = √((-7)² + 5²) = √74

u • z = ⟨2, 12⟩ • ⟨-7, 5⟩ = -14 + 60 = 46

and so

||w|| = √((2√37)² + 2•46 + (√74)²)

… = √(4•37 + 2•46 + 74)

… = √314 ≈ 17.720

Alternatively, without mentioning the dot product,

w = u + z = ⟨2, 12⟩ + ⟨-7, 5⟩ = ⟨-5, 17⟩

and so

||w|| = √((-5)² + 17²) = √314 ≈ 17.720

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2 years ago
The weight of
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10 move the decimal point over 3 spots
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3 years ago
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