Hi there!
200(20)^x > 500x + 400
Let's find the critical points of the inequality
200(20^x) = 500x + 400
Now we can divide both sides by 200
(200(20^x))/200 = (500x + 400)/200
20x^x = 5/2 x + 2
There are no critical points.
Thus,
The answer is: No solution
As always, it is my pleasure to help students like you.
Answer:
-2+k.5/n
Step-by-step explanation:
nsnsndksksnskksnsksnsnksnwkbsbssksj sosnanskzbwkssbkwwnkwsnwosbsndosnkssneosnenkssbkssnnkbwjwoswnks
135 because if you divide 90 by 2 you get 45 then add 45 and 90 and you get 135
You can simplify the fraction to get 2/5. If you convert this into a decimal you will get 0.4, so D is your answer.
Answer:

Step-by-step explanation:
Let the smaller number be
. Since they are consecutive even numbers, the larger number can be represented by
.
Therefore, we have the following equation:

Thus, the larger number is 