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sukhopar [10]
3 years ago
11

categorize the following graph is linear increasing, linear decreasing, exponential growth, or exponential decay.

Mathematics
1 answer:
OlgaM077 [116]3 years ago
3 0

Answer:

Exponential Decay is the answer

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I will mark you brainiest if you can answer this
Svet_ta [14]

The answer should be B bc the point is at 1 and it rises 2 and runs 3 to the left so it’s negative
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2 years ago
explain to make a apple pie you need 2 pounds of apples how many pounds do i need to make 20 apple pies
Andrews [41]
You do 2x20 which is basically 2x2 (4) add a zero and your answer is 40
7 0
2 years ago
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Set up a system of equations and then use your calculator to solve: In triangle ABC, the sum of angles and c is equal to three t
aalyn [17]

Answer:

Step-by-step explanation:

angle A = 40

angle B = 60

angle C = we don't know.

A + B + C = 180

C = 180 - A - B

C = 180 - 40 - 60

C = 80

40 + 60 + 80 = 180

180 = 180...It checks!

4 0
3 years ago
The weight distribution of parcels sent in a certain manner is normal with mean value 17 lb and standard deviation 3.3 lb. The p
Yakvenalex [24]

Answer: The value of c would be 26.514 lb.

Step-by-step explanation:

Since we have given that

Mean = 17 lb

Standard deviation = 3.3 lb

At 99%  level of significance, z = 2.58

So, it becomes,

Z=\dfrac{X-\mu}{\sigma}\\\\2.58=\dfrac{X-17}{3.3}\\\\2.58\times 3.3=X-17\\\\8.514+17=X\\\\X=25.514

So, the weight c would be

c=25.514+1\\\\c=26.514

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7 0
3 years ago
Integrate the following
enot [183]

I suppose you mean to have the entire numerator under the square root?

\displaystyle\int_2^4\frac{\sqrt{x^2-4}}{x^2}\,\mathrm dx

We can use a trigonometric substitution to start:

x=2\sec t\implies\mathrm dx=2\sec t\tan t\,\mathrm dt

Then for x=2, t=\sec^{-1}1=0; for x=4, t=\sec^{-1}2=\frac\pi3. So the integral is equivalent to

\displaystyle\int_0^{\pi/3}\frac{\sqrt{(2\sec t)^2-4}}{(2\sec t)^2}(2\sec t\tan t)\,\mathrm dt=\int_0^{\pi/3}\frac{\tan^2t}{\sec t}\,\mathrm dt

We can write

\dfrac{\tan^2t}{\sec t}=\dfrac{\frac{\sin^2t}{\cos^2t}}{\frac1{\cos t}}=\dfrac{\sin^2t}{\cos t}=\dfrac{1-\cos^2t}{\cos t}=\sec t-\cos t

so the integral becomes

\displaystyle\int_0^{\pi/3}(\sec t-\cos t)\,\mathrm dt=\boxed{\ln(2+\sqrt3)-\frac{\sqrt3}2}

7 0
3 years ago
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