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fomenos
3 years ago
11

What are the three equivalent to 6/9

Mathematics
2 answers:
Yuki888 [10]3 years ago
6 0

Answer:

2/3, 12/18 and 18/27

Step-by-step explanation:

Lapatulllka [165]3 years ago
6 0

Answer

Step 1 : add: 6+6 =12 and add : 9+9 give us 18 so 6/9=12/18 as a

equivalent continue with the same way: add 12+12=24 and 18+18=36 is

24/36 the last one add 24+24=48 and 36+36= 72 so the last

Equivalent is 48/72

Step 3: RELAX

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During a musical an orchestra is playing. As the music plays, the volume changes in the beginning of the piece can be modeled by
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Answer:

Kindly check explanation

Step-by-step explanation:

Given the model:

s = 10│x - 4│+ 50

s represents the sound level in decibels and x represents the number of measures of music played

To find x at s = 80

The equation becomes /

80 = 10│x - 4│+ 50

Subtract 50 from both sides of the equation

80 - 50 = 10 |x - 4| + 50 - 50

30 = 10 | x - 4 |

Divide both sides by 10

30/10 = 10|x - 4| / 10

3 = |x - 4|

|x - 4| is an absolute value expression

±3 = |x - 4|

x = 3 + 4 = 7

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3 years ago
⦁ Use both methods to find the distance between the points on the number line.
Vitek1552 [10]

Answer:

4 and 4

Step-by-step explanation:

Method A

1) Method A: Let 2 be the starting point and -2, the finishing one. Counting between 2 and -2, we can count a distance of 4 units. That's the simplest way, but not convenient to great numbers on the Number Line.

Method B:

There is no such thing as a negative distance, as a physical quantity. So this is the reason why we need to compute the absolute value of two numbers, which is simply what was done on Method B.

|2-(-2)|=|4|=4

As we are dealing with absolute values, the order is not relevant after all, the result remains the same. Take a look:

|-2-2|=|-4|=4

That's why the greater (2) or the lesser number (-2) can be the subtrahend (in bold within the brackets.

3 0
3 years ago
(1.1/1.2: Interpolating polynomials) Say we want to find a polynomialf(x) ofdegree 3,f(x) =a0+a1x+a2x2+a3x3,satisfying some inte
Hunter-Best [27]

(a) If

<em>f(x)</em> = <em>a</em>₀ + <em>a</em>₁ <em>x </em>+<em> a</em>₂ <em>x</em> ² + <em>a</em>₃ <em>x</em> ³

then from the given conditions we get the system of equations,

<em>f</em> (-1) = <em>a</em>₀ - <em>a</em>₁<em> </em>+<em> a</em>₂ - <em>a</em>₃ = -1

<em>f</em> (1) = <em>a</em>₀ + <em>a</em>₁<em> </em>+<em> a</em>₂ + <em>a</em>₃ = 2

<em>f</em> (2) = <em>a</em>₀ + 2<em>a</em>₁<em> </em>+ 4<em>a</em>₂ + 8<em>a</em>₃ = 1

<em>f</em> (3) = <em>a</em>₀ + 3<em>a</em>₁<em> </em>+<em> </em>9<em>a</em>₂ + 27<em>x</em> ³ = 5

(b) Similarly, if

<em>f(x)</em> = <em>a</em>₀ + <em>a</em>₁ <em>x </em>+<em> a</em>₂ <em>x</em> ² + <em>a</em>₃ <em>x</em> ³

then

<em>f'(x)</em> = <em>a</em>₁<em> </em>+<em> </em>2<em>a</em>₂ <em>x</em> + 3<em>a</em>₃ <em>x</em> ²

so that the given conditions yield the system,

<em>f</em> (1) = <em>a</em>₀ + <em>a</em>₁<em> </em>+<em> a</em>₂ + <em>a</em>₃ = 0

<em>f'</em> (1) = <em>a</em>₁<em> </em>+<em> </em>2<em>a</em>₂ + 3<em>a</em>₃ = 2

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Oduvanchick [21]
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Answer:

1. 0.6p

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2 years ago
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